Which of the following elements has the highest ionization energy?
1 answer:
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Answer:
*
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*
Explanation:
Hello,
At first, the molarities of NaClO and KF are computed as shown below:
Now, since both NaClO and KF are ionic, one proposes the dissociation reactions as:
In such a way, by writing the formation of HClO and HF respectively, due to the action of water, we obtain:
Now, the presence of OH⁻ immediately implies that Kb for both NaClO and KF must be known as follows:
In such a way, the law of mass action for each case is:
Now, by solving for the change for both the ClO⁻ and F⁻ equilibriums, we obtain:
Such results equal the concentrations of OH⁻ in each equilibrium, thus, the total concentration of OH⁻ result:
With which the pOH is:
And the pH:
In addition, the equilibrium concentrations of HClO and HF equals the change for each equilibrium as:
Best regards.
Answer:
Sulfur
Explanation:
<u>Valence electrons</u> are the group numbers. The group numbers are the numbers that go from left to right on the top. But since you can't have more than 8 valence electrons, the group numbers of 13-18, the valence electrons will actually be from 3-8. So 6 valence electrons would be group 16. That narrows it down a lot. The only elements in this group are oxygen, sulfur, selenium, tellurium, polonium, and livermorium.
Energy level are the period numbers. The period numbers are the numbers that go from top to bottom. So the 3rd energy level is the 3rd period. So when you look at the periodic table, under the 16 group and 3rd period, lies Sulfur.
