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iragen [17]
3 years ago
12

Which element would lose electrons during ionic bonding choose all that apply

Chemistry
1 answer:
yawa3891 [41]3 years ago
7 0

Answer:

All of them!

Explanation:

Since Mg, Li, Ca, and Cs are all in groups 1 and 2 of the periodic table, they are alkali/alkaline earth metals and will all lose electrons during ionic bonding.

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Atoms with a low electronegativity,like lithium,have a weak attractive force for electrons because
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they're close to filling their outer shell, fulfilling the octet rule

Explanation:

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How many TOTAL atoms are contained in 10 molecules of TNT, C7H5N3O6?
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Answer:7 atom of carbon+5atom of hydrogen +3atom of nitrogen +6 atom of oxygen =21

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Answer: b design procedure

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The human eye is a complex sensing device for visible light. The optic nerve needs a minimum of 2.0 × 10−17 J of energy to trigg
AveGali [126]
Number of photons can be calculated by dividing the needed energy by the energy per photon.

The minimum energy needed is given as 2 x 10^-17 joules
Energy per photon = hc / lambda where h is planck's constant, c is the speed of light and lambda is the wavelength
Energy per photon = (<span>6.626 x 10^-34 x 3 x 10^8) / (475 x 10^-9)
                              = 4.18 x 10^-19 J

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7 0
3 years ago
Hydrogen peroxide decomposes to water and oxygen at constant pressure by the following reaction: 2H2O2(l) → 2H2O(l) + O2(g) ΔH =
Mashcka [7]

<u>Answer:</u> The amount of heat released is -7.203 kJ

<u>Explanation:</u>

The given chemical equation follows:

2H_2O_2(l)\rightarrow 2H_2O(l )+O_2(g);\Delta H=-196kJ

To calculate the enthalpy change for 1 mole of the hydrogen peroxide, we use unitary method:

When 2 moles of hydrogen peroxide is reacted, the enthalpy of the reaction is -196 kJ

So, when 1 mole of hydrogen peroxide will react, the enthalpy of the reaction will be \frac{-196}{2}\times 1=-98kJ

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of hydrogen peroxide = 2.50 g

Molar mass of hydrogen peroxide = 34 g/mol

Putting values in above equation, we get:

\text{Moles of hydrogen peroxide}=\frac{2.50g}{34g/mol}=0.0735mol

  • To calculate the heat of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released

n = number of moles = 0.0735 moles

\Delta H_{rxn} = enthalpy change of the reaction = -98 kJ/mol

Putting values in above equation, we get:

-98kJ/mol=\frac{q}{0.0735mol}\\\\q=(-98kJ/mol\times 0.0735mol)=-7.203kJ

Hence, the amount of heat released is -7.203 kJ

8 0
3 years ago
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