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3 years ago

Inclined planes reduce the amount of effort needed to move an object, but increases

Chemistry

1 answer:

QveST [7]3 years ago

8 0

Inclined planes reduce the amount of effort needed to move an object, but increases the length of the ramp.

Explanation:

Mechanical advantage is the measure of amount of effort needed to move an object. The mechanical advantage can be calculated as the ratio of length of ramp to the height of ramp for an inclined plane.

As it is known that an object can be easily moved on an inclined plane than on a vertical plane, this is because, the inclined plane provides greater output force. But in that case, the effort required will be reduced with the cost of increasing the distance of the movement of object.

In other terms , the ramp's length of inclined planes has to get increased in order to reduce the amount of effort needed to move an object. This is because as the mechanical advantage has length of the ramp in the numerator, with the increase in numerator value or length value the mechanical advantage will also increase.

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koban [17]

Answer:

$Cu~+~PtCl_2->Pt~+~CuCl_2$

Explanation:

In this case, we can start with the formula of Platinum (II) Chloride. The cation is the atom at the left of the name (in this case $Pt^+^2$ ) and the anion is the atom at the right of the name (in this case $Cl^-$ ). With this in mind, the formula would be $PtCl_2$ .

Now, if we used metallic copper we have to put in the reaction only the copper atom symbol $Cu$ . So, we have as reagents:

$Cu~+~PtCl_2->$

The question now is: What would be the products? To answer this, we have to remember "single displacement reactions". With a general reaction:

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With this in mind, the reaction would be:

$Cu~+~PtCl_2->Pt~+~CuCl_2$

I hope it helps!

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