I believe C is the answer <span />
Answer: 0.86g/mL
Explanation:
Mass of empty cylinder = 23.731g
Mass of cylinder + liquid = 26.414g
Mass of the liquid = 26.414 — 23.731
= 2.683g
Volume of the liquid = 3.12mL
Density = Mass / volume
Density = 2.683g / 3.12mL
Density = 0.86g/mL
ANSWER: receptor-meditated endocytosis
I’m not sure if this is what you’re looking for but this is correct. Next time please add the full question and possible answers. HOPE this helps someone please leave thanks if so.
Many compunds have a terminal carbonyl
Aldehyde, Ketone, Carboxylic acid, Amide, Imide, Acid anhydride are the first that come to my mind.
<span>Ca(NO3)2 + Na2CO3 = CaCO3 + 2NaNO3
Yes a precipitate of Calcium Carbonate is formed since it is insoluble in water.
Mol Wt of Calcium Nitrate is 164. And that of Calcium Carbonate is 100.
One mole of Calcium Nitrate produces one mole of Calcium Carbonate.
i.e. 164 gms will produce 100gms of precipitate
So, 1.74gms of Calcium Carbonate will be obtained from 2.85gms Calcium Nitrate present in the original solution.</span>