Answer:
THE NORMAL BOILING POINT OF A SOLUTION CONTAINING 64.5 g OF QUINOLINE IN 500 g OF BENZENE IS 82.6 C
Explanation:
Boiling point = old boiling point + molarity * boiling point constant (Kb)
First, you calculate the number of moles of quinoline in the solution
number of moles = mass / molar mass
Since the molar mass of quinoline has been given as 129 g/mol
number of moles = 64.5 g / 129 g/mol
number of moles = 0.5 moles.
Next is to determine the molarity:
molarity = number of moles of solute / kilogram of solvent
molarity = 0.5 moles / 500/1000 kg
molarity = 0.5 / 0.5
molarity = 1 M
The new boiling point can then be calculated using the formula:
B. P = old B.P + Kb * molarity
B.P = 80.10 + 2.50 * 1
B.P = 80.10 + 2.50
B.P = 82.6 degree celsius
The radio wave travels at the speed of light so divide 8.00 x 10^7 by the speed of light.<span>
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2.34 moles titanium x (6.022 x 10^23)/1 mole titanium = 1.41 x 10^24
Answer:
CO2
Explanation:
CO2 or carbon dioxide is produced when iron is extracted from its ore. Carbon monoxide Co is used as reducing agent in iron extraction. In this reaction iron ore is reduced to iron and CO is oxidized to CO2 or carbon dioxide which is released in the process. There extraction of iron is redox reaction.