Answer:
0.0900 mol/L
Explanation:
<em>A chemist makes 330. mL of nickel(II) chloride working solution by adding distilled water to 220. mL of a 0.135 mol/L stock solution of nickel(II) chloride in water. Calculate the concentration of the chemist's working solution. Round your answer to significant digits.</em>
Step 1: Given data
- Initial concentration (C₁): 0.135 mol/L
- Initial volume (V₁): 220. mL
- Final concentration (C₂): ?
- Final volume (V₂): 330. mL
Step 2: Calculate the concentration of the final solution
We prepare a dilute solution from a concentrated one. We can calculate the concentration of the working solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁/V₂
C₂ = 0.135 mol/L × 220. mL/330. mL = 0.0900 mol/L
Answer:
In an electrophilic aromatic substitution (Friedel Crafts alkylation) first in the monoalkylation of the 1,4-dimethoxybenzenethe the methoxy groups redirects the substitution for ortho-para positions with respect to the electrophile that is going to enter (alkyl group) this is due to the increase in electron density in that position, that is , to the inductive effect.
According to the second incoming alkyl group there would be 3 positions available, from which it will choose the meta position in relation to the second methoxy group, since the alkyl group is a weak activator of the ortho meta positions and coincides with the position to which it redirects the second methoxy group.
They have high electron affinity
Answer:
Bullets
Explanation:
Ballistics is the analysis of projectiles and the only projectile in the list is a bullet.
<span>The atmosphere is composed
mainly of air molecules. And air molecules consist of 21% oxygen and 79%
nitrogen. Oxygen is used for a lot of things. It used for cellular respiration,
for humans to breathe and other complex chemical reactions that needs oxygen. Nitrogen
is one of the important nutrients mostly used in the soil of the plants. It is
used for protein synthesis. Nitrogen is also absorbed by the plants from the
and the soil to complete the necessary reactions. </span>
