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Darina [25.2K]
3 years ago
6

Find the product (-5a^2)^3•a^5

Mathematics
2 answers:
Oxana [17]3 years ago
4 0

Answer:

− 125a11

is the answer

wariber [46]3 years ago
3 0

The product of (-5a^2)^3•a^5 is (-125) \times a^{11}

<u>Solution:</u>

Given that we need to find the product of (-5a^2)^3•a^5

Some of the laws of exponents used to solve this sum are:

1) a^{m} \times a^{n}=a^{m+n}

2) \frac{a^{m}}{a^{n}}=a^{m-n}

Now solve the given expression,

\begin{array}{l}{\left(-5 a^{2}\right)^{3} \times a^{5}=(-5)^{3}\left(a^{2}\right)^{3} \times a^{5}} \\\\ {=(-5 \times-5 \times-5) \times\left(a^{6}\right) \times\left(a^{5}\right)} \\\\ {=(-125) \times\left(a^{6+5}\right)} \\\\ {=(-125) \times a^{11}}\end{array}

Hence the product is (-125) \times a^{11}

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Find a ∩ b if a = {2, 5, 8, 11, 14} and b = {1, 3, 5, 7}. {1, 2, 3, 5, 7, 8, 11, 14} {5}
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The intersection of given set a and b is a∩b = {5}.

According to the given question.

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