*Graph is attached with the answer*
Answer:
Total distance traveled by the car is 40 m
Explanation:
It can be seen from the graph that for the first 4 second car is moving with uniform acceleration and for next 2 second it has constant velocity
So, we solved this question in 2 parts
Part 1:
initial velocity = v₁ = 0 m/s
final velocity = v₂ = 10 m/s
time = t = 4 s
acceleration = a = (v₂ - v₁)/t
a = 10/4 = 2.5 m/s²
Using 3rd equation of motion
2as = v₂² - v₁²
2(2.5)s = 10²
s₁ = 100/5
s₁ = 20 m
Part 2:
s₂ = v₂t
s₂ = 10 × 2
s₂ = 20 m
Total distance = S = s₁ + s₂
= 20 + 20
S = 40 m
0.8611 g/cm ^2
Density = mass/ volume
Answer:
(a)
907.11 rad/s²
(b)
4082 rad
Explanation:
(a)
t = time taken = 3.00 s
w₀ = initial angular velocity of the drill = 0 rad/s
w = final angular velocity of the drill = 26000 rev/min = 26000
= 2721.33 rad/s
α = angular acceleration of the drill
t = time interval = 3.00 s
using the equation
w = w₀ + α t
2721.33 = 0 + α (3)
α = 907.11 rad/s²
(b)
θ = angle
using the equation
θ = w₀ t + (0.5) α t²
θ = (0) (3.00) + (0.5) (907.11) (3.00)²
θ = 4082 rad
Answer:
final velocity = 39.7 m/s
Explanation:
u = 1.44 m/s a = 4.48 m/s² t = 8.55 s v = ?
v = u + at
v = 1.44 + (4.48 x 8.55)
= 39.7 m/s
Hope this helps!