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mezya [45]
3 years ago
14

During a flood, a stream overflows its banks, and water covers the adjacent ____.

Physics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

Flood Plain

Explanation:

The amount of water that circulates through a river, the flow, varies in time and space. These variations define the hydrological regime of a river. Temporary variations occur during or just after episodes of rains or thaws. Much of the water that falls in the catchment basin circulates underground, or feeds underground aquifers and takes much longer to feed the river flow and can reach it days, weeks or months after the rain generated by the runoff. The runoff that goes to the river is what increases its flow. In extreme cases, flooding can occur when the water supply is greater than the river's ability to evacuate it, overflowing and covering nearby flat areas or floodplain. In this distribution between the runoff water (or stream) that goes directly to the channel and water that infiltrates, feeds the aquifers and maintains the flow in the river in times without precipitation depends largely on the geomorphological integrity of the entire river system .

In natural dynamics, the river systems have their own space that has been modeled by the floodwaters and is made up of the channel, the banks and the plain or flood plain. Its dimensions have been defined by the main flood events that this river has attended. Floodplains are wide and flat areas built by the river in its floodwaters. They are flooded frequently and are covered by sediments and nutrients that fertilize the soil act as natural reservoirs, reducing the speed of the downstream current. They store floodwater and rainfall in aquifers (underground area).

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The two cars collide at right angles in the intersection of two icy roads. Car A has a mass of 1965 kg and car B has a mass of 1
Sunny_sXe [5.5K]

Answer:

U2 = 47.38m/s = initial velocity of B before impact

Explanation:

An example of the diagram is shown in the attached file because of missing angle of direction in the question

Mass A, B are mass of cars

A = 1965

B =1245

U1 = initial velocity of A = 52km/hr

U2 = initial velocity of B

V = common final velocity of two cars

BU2 = (A + B)*V sin ¤ ...eq1 y plane

AU1 = (A + B) *V cos ¤ ....equ 2plane

From equ 2

V = AU1/(A + B)*cos ¤

Substitute V into equation 1

We have

U2 = (AU1/B)tan ¤ where ¤ = angle of direction which is taken to be 30°

Substitute all parameters to get

U2 = (1965/1245)*52 * tan 30°

U2 = 47.38m/s

8 0
4 years ago
Compare the de Broglie wavelength of a golf ball moving at 70.0 miles per hour (31.3 m/s) to that of an alpha particle moving at
sergiy2304 [10]

Answer:

1. Golf ball is in the range of only particulate detectable range

2, alpha partcle is in ultraviolet range of wavelength

3.bullet is in xray range of wavelength

All in the EMW spectrum

6 0
3 years ago
a specimen of oil having an initial volume of 5000cm³ is subjected to a pressure of 10⁴N/m² and the volume decreases by 0.20cm³.
inessss [21]

Answer:

 B = 2.5 10⁸ Pa

Explanation:

The volume modulus is defined by

           B = - \frac{P}{ \frac{\Delta V}{V} }

           

The negative fate is for the module to be positive since the volume change is negative

       

It is not necessary to reduce the volumes to the SI system, since they are both in the same units

             B = - \frac{10^4}{ \frac{-0.20}{5000} } = \frac{10^4}{4 \ 10^{-5} }

             B = 2.5 10⁸ Pa

4 0
3 years ago
In a carrom game, a striker weighs three times the mass of the other pieces, the carrom men and the queen, which each have a mas
Mila [183]

Answer:

- The final velocity of the queen is (3/2) of the initial velocity of the striker. That is, (3V/2)

- The final velocity of the striker is (1/2) of the initial velocity of the striker. That is, (V/2)

Hence, the relative velocity of the queen with respect to the striker after collision

= (3V/2) - (V/2)

= V m/s.

Explanation:

This is a conservation of Momentum problem.

Momentum before collision = Momentum after collision.

The mass of the striker = M

Initial Velocity of the striker = V (+x-axis)

Let the final velocity of the striker be u

Mass of the queen = (M/3)

Initial velocity of the queen = 0 (since the queen was initially at rest)

Final velocity of the queen be v

Collision is elastic, So, momentum and kinetic energy are conserved.

Momentum before collision = (M)(V) + 0 = (MV) kgm/s

Momentum after collision = (M)(u) + (M/3)(v) = Mu + (Mv/3)

Momentum before collision = Momentum after collision.

MV = Mu + (Mv/3)

V = u + (v/3)

u = V - (v/3) (eqn 1)

Kinetic energy balance

Kinetic energy before collision = (1/2)(M)(V²) = (MV²/2)

Kinetic energy after collision = (1/2)(M)(u²) + (1/2)(M/3)(v²) = (Mu²/2) + (Mv²/6)

Kinetic energy before collision = Kinetic energy after collision

(MV²/2) = (Mu²/2) + (Mv²/6)

V² = u² + (v²/3) (eqn 2)

Recall eqn 1, u = V - (v/3); eqn 2 becomes

V² = [V - (v/3)]² + (v²/3)

V² = V² - (2Vv/3) + (v²/9) + (v²/3)

(4v²/9) = (2Vv/3)

v² = (2Vv/3) × (9/4)

v² = (3Vv/2)

v = (3V/2)

Hence, the final velocity of the queen is (3/2) of the initial velocity of the striker and is in the same direction.

The final velocity of the striker after collision

= u = V - (v/3) = V - (V/2) = (V/2)

The relative velocity of the queen withrespect to the striker after collision

= (velocity of queen after collision) - (velocity of striker after collision)

= v - u

= (3V/2) - (V/2) = V m/s.

Hope this Helps!!!!

3 0
3 years ago
Read 2 more answers
A crane lifts an air conditioner to the top of a building. If the building is 12 m high, and the air conditioner has a mass of 2
Pepsi [2]

Work needed = 23,520 J

<h3> Further explanation </h3>

Given

height = 12 m

mass = 200 kg

Required

work needed by the crane

Solution

Work is the transfer of energy caused by the force acting on a moving object  

Work is the product of force with the displacement of objects.  

Can be formulated  

W = F x d  

W = Work, J, Nm  

F = Force, N  

d = distance, m  

F = m x g

Input the value :

W = mgd

W = 200 kg x 9.8 m/s²x12 m

W = 23520 J

8 0
3 years ago
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