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2 years ago

14

Abdou was explaining to a classmate that graphite is a good lubricant because it is bonded in layers that easily slip over each

other. Which image shows this quality? A P E X

2 answers:

Vladimir [108]2 years ago

7 0

Answer:

its the one that kind of looks like a shoe rack with 5 spears

Explanation:

its right yall

Kitty [74]2 years ago

4 0

Answer:

c

Explanation

I just took the test

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A muon is traveling at 0.988

AlexFokin [52]

As per Einstein's relation of relativity

$m = \frac{m_0}{\sqrt{1 - \frac{v^2}{c^2}}}$

here we know that

$m_0 = 207 m_e = 207 \times 9.11 \times 10^{-31} kg$

$m_0 = 1.88 \times 10^{-28} kg$

now here we know that

$v = 0.988 c$

now from above equation mass of the muon is given as

$m = \frac{1.88 \times 10^{-28}}{\sqrt{1 - 0.988^2}}$

$m = 1.22 \times 10^{-27} kg$

now for the momentum of muon we can use

$P = mv$

$P = 1.22 \times 10^{-27} \times 0.988(3 \times 10^8)$

$P = 3.62 \times 10^{-19} kg m/s$

so above is the momentum of muon

6 0

3 years ago

What is a definition for reactivity with vinegar?

STALIN [3.7K]

The answer to this is Chemical property.

6 0

3 years ago

Indicate the result of each of the following unit vector cross products (unit vector hat-symbols not shown): . kxi = . jxi= -jxk

Reil [10]

Answer:

Explanation:

The cross product of two vectors is given by

$\overrightarrow{A}\times \overrightarrow{B}=\left | \overrightarrow{A} \right |\left | \overrightarrow{B} \right |Sin\theta \widehat{n}$

Where, θ be the angle between the two vectors and \widehat{n} be the unit vector along the direction of cross product of two vectors.

Here, K x i = - j

As K is the unit vector along Z axis, i is the unit vector along X axis and j be the unit vector along axis.

The direction of cross product of two vectors is given by the right hand palm rule.

So, k x i = j

j x i = - k

- j x k = - i

i x i = 0

4 0

3 years ago

A thin, uniform rod is hinged at its midpoint. to begin with, one-half of the rod is bent upward and is perpendicular to the oth

bazaltina [42]

<span>Answer: initial I = (m/2)LÂ˛/3 + (m/2)LÂ˛ where L = Â˝ the length of the rod, and the vertical half can be treated as a point mass. initial I = mLÂ˛(1/6 + 1/2) = 2mLÂ˛/3 final I = m(2L)Â˛/3 = 4mLÂ˛/3 Since I has doubled and momentum is conserved, Ď‰ has halved. Ď‰ = 3.9 rad/s. Formulaically: 2mLÂ˛/3 * 7.8rad/s = 4mLÂ˛/3 * Ď‰</span>

5 0

3 years ago

According to the work-energy theorem, if work is done on an object, its potential and/or kinetic energy changes. Consider a car

Leni [432]

Answer:

The force of the car engine.

Explanation:

The work- energy theorem states that the work done on an object is equal to the change in its kinetic energy. Its expression is given by :

$W=\dfrac{1}{2}m(v^2-u^2)$

Also, W = F.d

$Fd=\dfrac{1}{2}m(v^2-u^2)$

Where

F is the force applied by the engine of car

d is the displacement

m is the mass of an object

u is the initial speed

v is the final speed

So, the force of the car engine increased the car’s kinetic energy. Hence, this is the required solution.

6 0

2 years ago