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fgiga [73]
3 years ago
14

Newtons first law stateS that object will move With a constant velocity if nothing acts on it. Does our every day experience con

tradict one of newtons law ? Explain
​
Physics
1 answer:
bazaltina [42]3 years ago
4 0

Answer:

hi

Explanation:

hi

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Fittoniya [83]
For distance vs time graphs, the slope stands for speed, as speed is a scalar, along with distance.
For displacement (position) vs time graphs, the slope stands for velocity, as velocity is a vector, along with displacement.
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3 years ago
A small spaceship whose mass is 1300 kg (including an astronaut) is drifting in outer space with negligible gravitational forces
Alexxandr [17]

Answer:

Explanation:

Relation between energy and momentum is as follows .

E = h c / λ

E / c = h / λ

h /λ = momentum of a photon

momentum of a photon  = E /c

= 11 x 10³ / 3 x 10⁸

= 3.67 x 10⁻⁵

In 4 days no of photon

= 4 x 24 x 60 x 60 = 345600 .

momentum of photon released

3.67 x 10⁻⁵  x 345600 .

= 12.68 kg m/s

This momentum will be imparted to spaceship .

12.68 = mv

12 .68 = 1300 x v

v = .00975 m /s

= 9.75 mm /s

8 0
3 years ago
Ok rlly guys help me
garik1379 [7]
Moving clouds. The doppler effect is specifically used to measure motion.
5 0
3 years ago
Read 2 more answers
A sound wave is often called a pressure wave because there are regions of high and low pressure established in them medium throu
Bingel [31]

Explanation:

A sound wave is often called a pressure wave because there are regions of high and low pressure established in them medium through which the sound wave travels. The regions of high pressure are known as <u>Compressions</u> and the regions of low pressure are known as <u>Rarefactions</u> . Sound waves are composed of compressions and rarefactions. Compressions are the parts where the molecules are congusted and pressed together. However in the rarefactions molecules are relax and have enough space for expansion. Sound waves are the logitudnal waves and always been defined as the motion of the medium particles parallel to the wave motion.

7 0
3 years ago
A block of mass 0.221 kg is placed on top of a light, vertical spring of force constant 5365 N/m and pushed downward so that the
Anvisha [2.4K]

Answer:

The maximum height above the point of release is 11.653 m.

Explanation:

Given that,

Mass of block = 0.221 kg

Spring constant k = 5365 N/m

Distance x = 0.097 m

We need to calculate the height

Using stored energy in spring

U=\dfrac{1}{2}kx^2...(I)

Using gravitational potential energy

U' =mgh....(II)

Using energy of conservation

E_{i}=E_{f}

U_{i}+U'_{i}=U_{f}+U'_{f}

\dfrac{1}{2}kx^2+0=0+mgh

h=\dfrac{kx^2}{2mg}

Where, k = spring constant

m = mass of the block

x = distance

g = acceleration due to gravity

Put the value in the equation

h=\dfrac{5365\times(0.097)^2}{2\times0.221\times9.8}

h=11.653\ m

Hence, The maximum height above the point of release is 11.653 m.

3 0
4 years ago
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