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Fiesta28 [93]
3 years ago
11

A heavy dart and a light dart are launched vertically by identical ideal springs. Both springs were initially compressed by the

same amount. There is no significant air resistance. Which of the following statements about these darts are correct? (There could be more than one correct choice.)a. Both darts reach the same maximum height. b. The heavy dart goes higher than the light dart. c. Both darts began moving upward with the same initial speed. d. The light dart goes higher than the heavy dart At the maximum height, both darts have the same gravitational potential energy.
Physics
1 answer:
sveticcg [70]3 years ago
8 0

Answer:

D

Explanation:

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A test charge of +4 µC is placed halfway between a charge of +6 µC and another of +2 µC separated by 20 cm. (a) What is the magn
S_A_V [24]

Answer:

(a) Magnitude: 14.4 N

(b) Away from the +6 µC charge

Explanation:

As the test charge has the same sign, the force that the other charges exert on it will be a repulsive force. The magnitude of each of the forces will be:

F_e = K\frac{qq_{test}}{r^2}

K is the Coulomb constant equal to 9*10^9 N*m^2/C^2, q and qtest is the charge of the particles, and r is the distance between the particles.

Let's say that a force that goes toward the +6 µC charge is positive, then:

F_e_1 = K\frac{q_1q_{test}}{r^2}=-9*10^9 \frac{Nm^2}{C^2} \frac{6*10^{-6}C*4*10^{-6}C}{(0.1m)^2} =-21.6 N

F_e_2 = K\frac{q_2q_{test}}{r^2}=9*10^9 \frac{Nm^2}{C^2} \frac{2*10^{-6}C*4*10^{-6}C}{(0.1m)^2} =7.2 N

The magnitude will be:

F_e = -21.6 + 7.2 = -14.4 N, away from the +6 µC charge

3 0
3 years ago
An electronic voltage is a varying electric current that represents information. True or False​
Contact [7]

Answer:

Explanation:

The word current is never used with voltage. Current, technically, is amperage. Amperage is defined much differently than voltage.

The answer is False.

4 0
3 years ago
What is the difference between Mass and Weight? ​
tiny-mole [99]

Answer: Mass is the quantity of matter in an object whereas weight is the force of gravity on an object.

Weight is dependent on gravity while mass is independent on gravity

Explanation:

3 0
3 years ago
Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.360 mm wide. The diffraction pattern is observed
Bumek [7]

Answer:

a) 0.0130 m

b') w' = =6.46*10^{-3] m

Explanation:

given data:

\lambda of light = 633 nm

width of siit a =0.360 mm

distance from screen = 3.75 m

a) the first minima is located at

sin\theta = \frac{\lambda}{a}

              == \frac{633 *10^{-9}}{.360*10^{-3}}

           \theta = 0.100

y_1 = dtan\theta_1 = 3.75*tan(0.100) = 6.54 *10^{-3} m

with of central fringe  = 2y_1 = 2*6.54 *10^{-3} = 0.0130 m

b)

width of the first bright fringe on either side of the central one = w' = y_2 -y_1

calculation for y_2

sin\theta = 2\frac{\lambda}{a}

              = = 2*\frac{633 *10^{-9}}{.360*10^{-3}}

             \theta  = 2*0.100 = 0.200

y_2 = dtan\theta_1 = 3.75*tan(0.200) =0.0130 m

w' = 0.0130  -6.54 *10^{-3}

w' = =6.46*10^{-3] m

6 0
3 years ago
What is a key difference between cell signaling by a cell-surface receptor and cell signaling by an intracellular receptor?
Art [367]

CORRECT ANSWER:

a- Cell-surface receptors bind polar signaling molecules; intracellular receptors bind nonpolar signaling molecules.

STEP-BY-STEP EXPLANATION:

The complete question from book is

According to Figure 9.6, what is a key difference between cell signaling by a cell-surface receptor and cell signaling by an intracellular receptor?

a- Cell-surface receptors bind polar signaling molecules; intracellular receptors bind nonpolar signaling molecules.

b- Signaling molecules that bind to cell-surface receptors lead to cellular responses restricted to the cytoplasm; signaling molecules that bind to intracellular receptors lead to cellular responses restricted to the nucleus.

c- Cell-surface receptors bind to specific signaling molecules; intracellular receptors bind any signaling molecule.

d- Cell-surface receptors typically bind to signaling molecules that are smaller than those bound by intracellular receptors.

e- None of the other answer options is correct.

3 0
3 years ago
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