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Fiesta28 [93]
4 years ago
11

A heavy dart and a light dart are launched vertically by identical ideal springs. Both springs were initially compressed by the

same amount. There is no significant air resistance. Which of the following statements about these darts are correct? (There could be more than one correct choice.)a. Both darts reach the same maximum height. b. The heavy dart goes higher than the light dart. c. Both darts began moving upward with the same initial speed. d. The light dart goes higher than the heavy dart At the maximum height, both darts have the same gravitational potential energy.
Physics
1 answer:
sveticcg [70]4 years ago
8 0

Answer:

D

Explanation:

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A certain electric circuit obeys Ohm's law. If the resistance of the circuit is doubled, what will happen to the current through
netineya [11]

Answer:

currrent will be halved

Explanation:

v = ir

v/r = i      multiply both sides by  1/ 2

v / (2r) = 1/2 i  

4 0
3 years ago
A 12 volt battery in a motor vehicle is capable of supplying the starter motor with 150 A. It is noticed that the terminal volta
qwelly [4]

Answer:0.0133 \Omega

Explanation:

Given

Voltage=12 V

Current(I)=150 A

V_{terminal}=10 V

r_{internal}=\frac{\Delta V}{I}

r_{internal}=\frac{12-10}{150}

r_{internal}=\frac{2}{150}=0.0133 \Omega

4 0
3 years ago
The moon is 3x10^5 km away from Nepal and the mass of the moon is 7x10^22 kg. Calculate the force with which the Moon pulls ever
hammer [34]

Answer:

Approximately 5.19 \times 10^{-5}\; \rm N.

Explanation:

Let G denote the gravitational constant. (G \approx 6.67 \times 10^{-11} \; \rm N \cdot kg^{-2} \cdot m^{2}.)

Let M and m denote the mass of two objects separated by r.

By Newton's Law of Universal Gravitation, the gravitational attraction between these two objects would measure:

\displaystyle F = \frac{G \cdot M \cdot m}{r^{2}}.

In this question: M = 7 \times 10^{22}\; \rm kg is the mass of the moon, while m = 1\; \rm kg is the mass of the water. The two are r = 3\times 10^{5}\; \rm km apart from one another.

Important: convert the unit of r to standard units (meters, not kilometers) to reflect the unit of the gravitational constant G.

\displaystyle r = 3 \times 10^{5}\; \rm km \times \frac{10^{3}\; \rm m}{1\; \rm km} = 3 \times 10^{8}\; \rm m.

\begin{aligned} F &= \frac{G \cdot M \cdot m}{r^{2}} \\ &= \frac{6.67 \times 10^{-11}\; \rm N \cdot kg^{-2}\cdot m^{2} \times 7 \times 10^{22}\; \rm kg \times 1\; \rm kg}{(3 \times 10^{8}\; \rm m)^{2}} \\ &\approx 5.19 \times 10^{-5} \; \rm N\end{aligned}.

5 0
3 years ago
How can you tell if a christmas tree light bulb is burned out just by looking at it?
zubka84 [21]
You can tell by making sure that the lights are unplugged and tighten lights then plug it in if I didn't work it's burnt :) hope it works
6 0
3 years ago
Read 2 more answers
As you approach a bicyclist traveling in your lane, adjust your speed and position and do not pass if the road is too _______ fo
tatiyna

Answer:

correct answer is narrow

Explanation:

solution

when we pass someone riding bicycle ahead you then we should decrease our speed and increase the distance between you and bicyclist

and we should ride on road with very predictable manner and we should ride in straight line and if If road is too narrow for a bicycle

then we should ride vehicle to travel side by side so bicyclist should occupy lane until it safe

so here correct option is narrow

5 0
3 years ago
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