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4 years ago

What is 8x+2y-10 over 2

Mathematics

2 answers:

puteri [66]4 years ago

4 0

Answer:

Step-by-step explanation:

= 4x + y - 5

sertanlavr [38]4 years ago

3 0

Answer:

Step-by-step explanation:

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PLEASE HELP ME ASAP. Thanks

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67 Animals. Hope this helps!

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3 years ago

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Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

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3 years ago

9. The ages of A and B are in the ratio 3:5. Four years later,

Tom [10]

Answer:

A = 15 B = 25 in four years 19+29 = 48

Step-by-step explanation:

age A and B ratio is 3 to 5

A+4 + B+4 = 48

A + B = 40

A/B = 3/5 A = 3B/5

A + B = 40

3B/5 + B = 40

3B + 5B = 200 multiple both sides by 5

8B = 200

B = 25

A = 3B/5

A = 3(25)/5

A = 15

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3 years ago

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The white chocolates cost her 3 dollars per pound and the dark chocolates cost her 4 dollars per pound Denise spends 27 dollars

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I believe its 8

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2 years ago

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inna [77]

it means the distance around a two dimensional shape.

To find the perimeter, add all the side lengths

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