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VladimirAG [237]
3 years ago
9

An area reserved for a parking lot is 80 feet long and 77 feet wide. The stalls of the lot are at 90° angles to two one-way aisl

es. Each aisle is 80 feet by 10 feet. The three areas set aside for the parking spaces are congruent rectangles. An area reserved for parking is 80 feet long and 77 feet wide. Three areas are set aside for parking and 2 aisles are in between. Each aisle is 80 feet by 10 feet. Each parking space will be 19 feet by 8 feet. What is the maximum number of parking spaces that will fit in the lot? 10 30 35 40
Mathematics
2 answers:
babunello [35]3 years ago
7 0

Answer:

30

Step-by-step explanation:

lilavasa [31]3 years ago
4 0

Answer:

30

Step-by-step explanation

We have 3 areas for parking and 2 aisles.

Each aisle is 10 ft wide , we have two we have 20 ft for aisles width then total width available for stalls

77  -  20  =  57

And each stall is 19 feet long then      57/19  = 3

And 80 ft long of the lot will permit 10 cars

Then we have each individuals set of stall with  10 parking places

Therefore

3 * 10  =  30

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\sf{\red{ANSWER \: \: :}}

x = 18 1/3

\sf{\purple{EXPLANATION \: \: :}}

x - 20 + 2x = 35

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3x = 35 + 20

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</span>
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Read 2 more answers
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