Answer:
65
Explanation:
estion
Al comenzar la reacción: N2(g) + 2O2(g) ------> 2NO2(g) existe 1 mol de N2 y 2 moles de O2 y al
finalizarla está presente una mezcla formada por 2,2 moles en total, ¿cuál es el rendimiento para la
reacción?
Answer: The statement, you've just prepared an aqueous solution is true.
Explanation:
When one or more number of substances are dissolved in a solvent like water then solution formed is called an aqueous solution.
For example, when a hot drink is made by dissolving a teaspoon of instant coffee and a teaspoon of sugar in a cup of hot water is an aqueous solution.
Here, both coffee and sugar are solute whereas hot water is the solvent.
Thus, we can conclude that the statement, you've just prepared an aqueous solution is true.
Buoyancy is a condition in which a physical body's average density is equal to the density of the fluid in which it is immersed.
The buoyancy offsets the force of gravity that would otherwise cause the object to sink (if the body's density is greater than the density of the fluid in which it is immersed) or rise (if it's less). An object that has neutral buoyancy will neither sink nor rise.
Hope this helps! xx
Complete Question
The complete question is shown on the first uploaded image
Answer:
The pressure is ![[O_2] = 4.8 *10^{-5} \ atm](https://tex.z-dn.net/?f=%5BO_2%5D%20%3D%20%204.8%20%2A10%5E%7B-5%7D%20%5C%20atm)
Explanation:
From the question we are told that
The pressure of 
is ![[SO_3 ] = 0.63 \ atm](https://tex.z-dn.net/?f=%5BSO_3%20%5D%20%3D%20%200.63%20%5C%20atm)
The pressure of 
is ![[SO_ 2] = 0.30 \ atm](https://tex.z-dn.net/?f=%5BSO_%202%5D%20%20%3D%20%200.30%20%5C%20atm)
The equilibrium constant is 
The reaction is
⇔ 
Generally the equilibrium constant is mathematically represented as
=> ![[O_2] = \frac{k_p * [SO_3] ^2 }{[SO_2]^2}](https://tex.z-dn.net/?f=%5BO_2%5D%20%3D%20%20%5Cfrac%7Bk_p%20%2A%20%5BSO_3%5D%20%5E2%20%7D%7B%5BSO_2%5D%5E2%7D)
substituting values
![[O_2] = \frac{1.2 *10^{-5} * 0.60 ^2 }{0.30^2}](https://tex.z-dn.net/?f=%5BO_2%5D%20%3D%20%20%5Cfrac%7B1.2%20%2A10%5E%7B-5%7D%20%2A%200.60%20%5E2%20%7D%7B0.30%5E2%7D)
