Find moles:
<span>36.0 g of glucose divided by 180 g/mol = 0.200 moles of glucose </span>
<span>find molarity: </span>
<span>0.200 moles of glucose / 2 litres = 0.100 Molar solution </span>
Answer:
11 molecules of CH4.
23 atoms of C is the leftover.
Explanation:
Hello!
In this case, for the formation of methane:

We can see there is an excess of carbon based on their stoichiometry, because the needed amount of hydrogen gas molecules would be:

Thus, the formed molecules of methane are computed below:

In such a way, the leftover of carbon atoms are:

Best regards!
Answer:
Depends on what are you refering to
Explanation:
So depending on what you are looking for (your question is quite vauge)
there are 5 atoms of the comopound (K2CO3)
within that compound, there are 2 atoms of Potassium and 1 atom of Carbonate. Within Carbonate there are 4 atoms (1 carbon and 3 oxygens)
so answers may be
5, 15, or 25.
I hope this helps.
I believe the answer you are looking for is the 4th one.
Molarity of solution is mathematically expressed as,
M =

We know that volume = mass/density
Given: mass of solution = 100 g, Density = 1.34 g/ml
∴ volume = 100/1.34 = 88.49 ml = 0.08849 l
Also, we know that molecular weight of sucrose = 342.3 g/mol
∴M =

= 6.979 M
Thus, molarity of solution is 6.979 M