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3 years ago

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Using the van der Waals equation, calculate the pressure for a 1.25 mol sample of xenon contained in a volume of 1.000L at 75Â°C

; a = 4.194 L2 atm/mol2 and b = 0.05105 L/mol for Xe. Compare these results to that predicted by the ideal gas law.

1 answer:

alina1380 [7]3 years ago

5 0

Answer:

ABC

Explanation:

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Distinguish between climate and atmosphere.

nignag [31]

What are you talking about and what’s the question

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3 years ago

Calculate the Equilibrium constant Kc at 25 C from the free - energy change for the following reaction . Zn(s) + 2Ag+(aq)<---

FinnZ [79.3K]

Answer: $Kc=1.24*10^5^2$

Explanation: For the given reaction:

$Kc=\frac{[Zn^+^2]}{[Ag^+]^2}$

Concentrations of the ions are not given so we need to think about another way to calculate Kc.

We can calculate the free energy change using the standard cell potential as:

$\Delta G^0=-nFE^0_c_e_l_l$

$E^0_c_e_l_l$ can be calculated using standard reduction potentials.

Standard reduction potential for zinc is -0.76 V and for silver, it is +0.78 V.

$E^0_c_e_l_l$ = $E^0_c_a_t_h_o_d_e+E^0_a_n_o_d_e$

Reduction takes place at anode and oxidation at cathode. As silver is reduced, it is cathode. Zinc is oxidized and so it is anode.

$E^0_c_e_l_l$ = 0.78 V - (-0.76 V)

$E^0_c_e_l_l$ = 0.78 V + 0.76 V

$E^0_c_e_l_l$ = 1.54 V

Value of n is two as two moles of electrons are transferred in the cell reaction F is Faraday constant and its value is 96485 C/mol of electron .

$\Delta G^0=-(2*96485*1.54)$

$\Delta G^0$ = -297173.8 J

Now we can calculate Kc using the formula:

$\Delta G^0=-RTlnKc$

T = 25+273 = 298 K

R = $8.314JK^-^1mol^-^1$

--297173.8 = -(8.314*298)lnKc

297173.8 = 2477.572*lnKc

$lnKc=\frac{297173.8}{2477.572}$

lnKc = 119.946

$Kc=e^1^1^9^.^9^4^6$

$Kc=1.24*10^5^2$

5 0

4 years ago

Which is a property of an ideal gas?

AlekseyPX

HEY THERE!

THE ANSWER IS: the properties of an ideal gas are: An ideal gas consists of a large number of identical molecules. The volume occupied by the molecules themselves is negligible compared to the volume occupied by the gas. The molecules obey Newton's laws of motion, and they move in random motion.

CREDITS:<span>physics.bu.edu/~duffy/py105/Idealgas.htm</span>

6 0

4 years ago

Read 2 more answers

69g of sodium reacts with chlorine to produce sodium chloride. calculate the number of moles of chlorine required to react with

Rus_ich [418]

Answer:

3 moles of $Cl^{-}$ is needed for $Na^{+}$ to be fully consumed.

Explanation:

For the balanced equation:

$Na^{+} + Cl^{-}$ ⇒ $NaCl$

First, find the moles of Na corresponding to the 69g used the general definition of mol:

$mol Na^{+} = \frac{69 g}{23 g/mol } = 3mol$

We observe that the equation is balanced and the stoichiometric ratio between them is 1: 1.

According to this, one mole of Na will react with one mole of Cl.

3 moles of $Cl^{-}$ is needed for $Na^{+}$ to be fully consumed.

7 0

3 years ago

A package of aluminum foil contains 50. ft2 of foil, which weighs approximately 8.5 oz . aluminum has a density of 2.70 g/cm3. w

Serhud [2]

Hello!

We have the following data:

Area (A) = 50 square feet
Mass (m) = 8.5 ounces
Density (d) = 2.70 g/cm³
Volume (V) = ?
Thickness (T) =? (in mm)

To move on, we must transform the area of 50 ft² in cm², let's see:

1 ft² ------- 929,0304 cm²
50 ft² ----- A

$A = 50*929,0304$

$\boxed{A = 46451,52\:cm^2}\Longleftarrow(Area)$

In the same way, we will convert the mass of 8.5 oz in grams, see:

1 oz -------- 28,3495 g
8,5 oz ------- m

$m = 8,5*28,3495$

$\boxed{m = 240,97075\:g}\Longleftarrow(mass)$

Knowing that the density is 2.70 g/cm³ and the mass is 240.97075 g, we will find the volume, applying the data in the density formula we have:

$d = \dfrac{m}{V} \to V = \dfrac{m}{d}$

$V = \dfrac{240,97075\:\diagup\!\!\!\!\!g}{2,70\:\diagup\!\!\!\!\!g/cm^3}$

$V = 89,24842593... \to \boxed{V \approx 89,25\:cm^3}$

The statement wants to find the thickness of the packaging, for this we have some important data, such as: V (volume) = 89,25 cm³ and Area (A) = 46451,52 cm² and T (thickness) =? (in mm)

In the calculations of Costs in Surface Treatment of a part within the flat geometry, we will use the following formula:

$V (volume) = A (Area) * T (Thickness)$

$89,25\:cm^3 = 46451,52\:cm^2\:*\:T$

$46451,52\:cm^2*T = 89,25\:cm^3$

$T = \dfrac{89,25\:cm^3}{46451,52\:cm^2}$

$T = 0,001921358009...\:cm$

We will convert to millimeters, going through a decimal place on the right

$T = 0,01921358009..\:mm$

$\boxed{\boxed{T \approx 0,0192\:mm\:or\:T\approx \:1,92*10^{-2}\:mm}}\end{array}}\Longleftarrow(thickness)\qquad\checkmark$

Hope this helps! :))

8 0

3 years ago