The combustion reaction of octane is as follow,
C₈H₁₈ + 25/2 O₂ → 8 CO₂ + 9 H₂O
According to balance equation,
8 moles of CO₂ are released when = 114.23 g (1 mole) Octane is reacted
So,
6.20 moles of CO₂ will release when = X g of Octane is reacted
Solving for X,
X = (114.23 g × 6.20 mol) ÷ 8 mol
X = 88.52 g of Octane
Result:
88.52 g of Octane is needed to release 6.20 mol CO₂.
Given the choices;
a) Bourdon gauge flowmeter
b) Hudson gauge flow meter
c) Constant flow selector
d) pressure compensated flowmeter.
The one that can only be used upright is the pressure-compensated flowmeter. Compensated flowmeters work with a variable orifice and fixed pressure. They read back pressure, and take into account resistance changes down stream from the needle valve. If pressure exceeds 50psig downstream, flow ceases.
Answer:
dark coloured rock with coarse grains in parallel layers
Explanation:
The answer would be Propane. The formula for Propane is C3H8
