Answer:
13.4 (w/w)% of CaCl₂ in the mixture
Explanation:
All the Cl⁻ that comes from CaCl₂ (Calcium chloride) will be precipitate in presence of AgNO₃ as AgCl.
To solve this problem we must find the moles of AgCl = Moles of Cl⁻. As 2 moles of Cl⁻ are in 1 mole of CaCl₂ we can find the moles of CaCl₂ and its mass in order to find mass percent of calcium chloride in the original mixture.
<em>Moles AgCl - Molar mass: 143.32g/mol -:</em>
0.535g * (1mol / 143.32g) = 3.733x10⁻³ moles AgCl = Moles Cl⁻
<em>Moles CaCl₂:</em>
3.733x10⁻³ moles Cl⁻ * (1mol CaCl₂ / 2mol Cl⁻) = 1.866x10⁻³ moles CaCl₂
<em>Mass CaCl₂ -Molar mass: 110.98g/mol-:</em>
1.866x10⁻³ moles CaCl₂ * (110.98g/mol) = 0.207g of CaCl₂ in the mixture
That means mass percent of CaCl₂ is:
0.207g CaCl₂ / 1.55g * 100 =
<h3>13.4 (w/w)% of CaCl₂ in the mixture</h3>
Answer: Electric charges are of two general types: positive and negative.
Hope this helps... Stay safe and have a great day.... :D
Answer:
Explanation:
Hello!
In this case, for the reaction:
In such a way, via the rate proportions, that is written considering the stoichiometric coefficients, we obtain:
Whereas the reactants, CO and H2 have negative stoichiometric coefficients; therefore the rate of disappearance of hydrogen gas is related to the rate of appearance of methanol as shown below:
Which means that the rate of disappearance of hydrogen gas is negative and the rate of appearance of methanol is positive.
Regards!
Answer:
Carbon-14 or C-14
Explanation:
Since the isotope is a carbon isotope, it means the the atomic number of the isotope is 6.
The atomic number of an element is the proton number.
Therefore, the isotope has a proton number of 6
Now we need to obtain the mass number of isotope in order to write the symbol of the isotope. This is illustrated below:
Mass number = Proton +Neutron
Proton = 6
Neutron = 8
Mass number = 6 + 8
Mass number = 14
Therefore, the symbol of the isotope is carbon-14 or C-14
Answer:
3.43 L
Explanation:
By the ideal gas law, when there is a state change, the quantities can be calculated by:
P1*V1/T1 = P2*V2/T2
Where P is the pressure, V is the volume, T is the temperature in K, 1 is the initial state, and 2 the final state.
P1 = 720 kPa, V1 = 562 mL, T1 = 45°C + 273 = 318 K
STP: P = 1 atm = 101.325 kPa, T = 273 K
720*562/318 = 101.325*V2/273
0.371153846V2 = 1272.45283
V2 = 3428 mL = 3.43 L
