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Dominik [7]
3 years ago
10

In a quasi-static isobaric expansion, 700 J of work are done by the gas. If the gas pressure is 0.40 atm, what is the fractional

increase in the volume of the gas, assuming it was originally at 22.0 L?
Chemistry
1 answer:
nordsb [41]3 years ago
5 0

Answer : The fractional increase in the volume of the gas is, 1.78

Explanation :

Formula used to calculate the work done by the gas in quasi-static isobaric expansion is:

w=p\times dV

Isobaric means, at constant pressure.

w=p\times (V_f-V_i)

where,

w = work done by the gas = 700 J = 6.909 L.atm    (1 L.atm = 101.32 J)

p = pressure of the gas = 0.40 atm

V_f = final volume = ?

V_i = initial volume = 22.0 L

Now put all the given values in the above formula, we get:

w=p\times (V_f-V_i)

6.909L.atm=0.40atm\times (V_f-22.0)L

V_f=39.3L

Now we have to calculate the fractional increase in the volume of the gas.

Fractional increase in the volume of the gas = \frac{V_f}{V_i}

Fractional increase in the volume of the gas = \frac{39.3L}{22.0L}

Fractional increase in the volume of the gas = 1.78

Thus, the fractional increase in the volume of the gas is, 1.78

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Explanation:

Hello there!

In this case, we can divide the problem in three stages: (1) determine the empirical formula with the combustion analysis, (2) compute the molar mass of acid via the moles of the acid in the neutralization and (3) determine the molecular formula.

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As they cannot be fractions.

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n_{acid}=0.0279mol

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Best regards!

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