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Georgia [21]
3 years ago
7

What is the atomic mass number of an isotope that has an atomic number of 5 and includes 6 neutrons?

Chemistry
2 answers:
irinina [24]3 years ago
8 0

The answer should be; 11

The atomic mass number is found by combining the number of protons and neutrons

Hope this helps :)

tatuchka [14]3 years ago
7 0

The correct answer is 11

Explanation:

In chemistry, each atom contains protons, neutrons, and electrons. The atomic mass number of an isotope (a variant of a chemical element) can be determined by adding the number of protons and neutrons. Additionally, the number of protons is equivalent to the atomic number that is usually the same according to the element. Additionally, the number of electrons has no or little influence on the atomic mass number. This implies, if an isotope has an atomic number of 5 it has 5 protons and this added to the 6 neutrons of the isotope makes the atomic mass number of this isotope 11 or 5 protons + 6 neutrons = 11 (atomic mass number).

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Dorothy left a frozen juice pop out on the counter. When she returned, the juice pop had melted into a liquid. Which of the foll
Brums [2.3K]

Answer:

B) The molecules were closer together when the juice pop was frozen.

8 0
3 years ago
If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what i
Ostrovityanka [42]

Consider the isomerization of butane with equilibrium constant is 2.5 .The system is originally at equilibrium with :

[butane]=1.0 M , [isobutane]=2.5 M

If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what is the equilibrium concentration of each gas?

Answer:

The equilibrium concentration of each gas:

[Butane] = 1.14 M

[isobutane] = 2.86 M

Explanation:

Butane  ⇄  Isobutane

At equilibrium

1.0 M               2.5 M

After addition of 0.50 M of butane:

(1.0 + 0.50) M               -

After equilibrium reestablishes:

(1.50-x)M            (2.5+x)

The equilibrium expression will wriiten as:

K_c=\frac{[Isobutane]}{[Butane]}

2.5=\frac{2.5+x}{(1.50-x)}

x = 0.36 M

The equilibrium concentration of each gas:

[Butane]= (1.50-x) = 1.50 M - 0.36M = 1.14 M

[isobutane]= (2.5+x) = 2.50 M + 0.36 M = 2.86 M

3 0
3 years ago
Measurements show that unknown compound X has the following composition: element mass % carbon 41.0% hydrogen 4.58% oxygen 54.6%
anastassius [24]

Answer:

CHO

Explanation:

Carbon = 41%,  Hydrogen = 4.58%, oxygen = 54.6%

Step 1:

Divide through by their respective relative atomic masses

41/ 12,         4.58/1,         54.6/16

3.41              4.58            3.41

Step 2:

Divide by the lowest ratio:

3.41/3.41,      4.58/3.41,     3.41/3.41

1,                    1,                  1

Hence the empirical formula is CHO

8 0
3 years ago
Give five properties of water.
Gelneren [198K]
Polarity, cohesion, adhesion, surface tension, high specific heat, and evaporating cooling
3 0
2 years ago
Read 2 more answers
The equilibrium for the reaction between (ch3)2nh a weak base
nadezda [96]

The equilibrium for the dissolution of the weak base is ;(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH3^+(aq) + OH^-(aq)

<h3>What is a weak base?</h3>

A weak base is one that does not ionize completely in solution. As such, a weak base will have a very low base dissociation constant Kb reflecting its minimal dissociation in solution.

The question is incomplete hence we are are unable to work out the equilibrium but in solution it will look like this;

(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH3^+(aq) + OH^-(aq)

Learn more about weak base: brainly.com/question/4131966

7 0
2 years ago
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