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cricket20 [7]
3 years ago
7

Convert 150 g/L to the unit g/mL.

Chemistry
1 answer:
inn [45]3 years ago
4 0
The correct answer is C 0.15 g/mL.
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Sufficient strong acid is added to a solution containing na2hpo4 to neutralize one-half of it. what will be the ph of this solut
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Assuming that the initial pH is pHi.
The initial concentration of [OH-] is
[OH]- = 10^(14 - pHi)

Since half of the Na2HPO4 is neutralized, the concentration of [OH-] will be reduced to half. The new pH will be
[OH-]/2 = 10^(14 - pHi)/2 = 10^(14 - pH)
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