Convert 150 g/L to the unit g/mL.

Describe the intermolecular forces that must be overcome to convert these substances from a liquid to a gas: (a) SO2, (b) CH3COO

Andre45 [30]

You need to find which intermolecular forces are between the molecules
dipole-dipole,h bonds, etc.
I'm not very good at explaining but this is what my prof said to help us

Identify the class of the molecule or molecules you are given. Are they nonpolar species, ions or
do they have permanent dipoles? Is there only one species or are there two?
In the case of ONE species (i.e., a pure substance), the intermolecular forces will be between
molecules of the same type. So if you are dealing with ions, the intermolecular forces will be ION-
ION or IONIC. If you are dealing with dipoles, then the intermolecular forces will be DIPOLE-
DIPOLE. If you are dealing with nonpolar species, the intermolecular forces will be DISPERSION
or VAN DER WAALS or INDUCED DIPOLE-INDUCED DIPOLE (the last three are desciptions
of the same interaction; regrettably we cannot call them nonpolar-nonpolar!).
In the case of TWO species (i.e., a mixture), the intermolecular forces will be between molecules of
one type with molecules of the second type. For example, ION-DIPOLE interactions exist between
ions dissolved in a dipolar fluid such as water.

7 0

3 years ago

At what temperature, in Kelvin, will a 250 milliliter cylinder containing 0.100 moles of helium gas have a pressure of 2.50 atmo

lozanna [386]

Use the ideal gas formula-----> PV= nRT

P= 2.50 atm
V= 250 mL= 0.250 L
n= 0.100 moles
R= 0.0821 atmxL/molesxK
T= ?

T= PV/nR

T= (2.50 atm x 0.250 L) / (0.100 moles x 0.0821)= 76.1 K

7 0

3 years ago

Read 2 more answers

What is the correct noble gas configuration for Ba?

kvasek [131]

I think the answer is [Xe] 6s2

8 0

3 years ago

What is the splitting of the signal in the 1H NMR spectrum for the methyl protons of 1-bromo-2-methylpropane?

Arada [10]

Answer:

doublet

Explanation:

Proton MNR is used for the determination of no. of equivalents protons in a molecule

In the molecule, single NMR signal is produced for each set of protons.

Signal splitting is called spin-spin coupling and the splitting of signals depends upon the no. of neighboring proton.

The no. of signal for a proton is equal to n+1, where n is neighboring protons.

In 1-bromo-2-methylpropane, neighboring proton for both methyl protons are one. But the chemical environment of both the methyl protons are different.

Neighboring proton for methyl protons = 1

No. of signal for methyl protons = 1+1 =2

Hence, two doublets will be generated for each set of methyl protons. protons.

3 0

3 years ago

Calculate the fraction of atoms in a sample of argon gas at 400 K that have an energy of 10.0 kJ or greater.

nikdorinn [45]

Answer:

The answer to this can be arrived at by clculating the mole fraction of atoms higher than the activation energy of 10.0 kJ by pluging in the values given into the Arrhenius equation. The answer to this is 20.22 moles of Argon have energy equal to or greater than 10.0 kJ

Explanation:

From Arrhenius equation showing the temperature dependence of reaction rates.

$K = Ae^{\frac{Ea}{RT} }$ where

k = rate constant

A = Frequency or pre-exponential factor

Ea = energy of activation

R = The universal gas constant

T = Kelvin absolute temperature

we have

$f = e^{\frac{Ea}{RT} }$

Where

f = fraction of collision with energy higher than the activation energy

Ea = activation energy = 10.0kJ = 10000J

R = universal gas constant = 8.31 J/mol.K

T = Absolute temperature in Kelvin = 400K

In the Arrhenius equation k = Ae^(-Ea/RT), the factor A is the frequency factor and the component e^(-Ea/RT) is the portion of possible collisions with high enough energy for a reaction to occur at the a specified temperature

Plugging in the values into the equation relating f to activation energy we get

$f = e^{\frac{10000J}{(8.31J/((mol)(K)))(400K)} }$ or f = $e^{3.01}$ = 20.22 moles of argon have an energy of 10.0 kJ or greater

5 0

3 years ago