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cricket20 [7]
3 years ago
7

Convert 150 g/L to the unit g/mL.

Chemistry
1 answer:
inn [45]3 years ago
4 0
The correct answer is C 0.15 g/mL.
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Kepler and Newton studied the movement of planets. Kepler studied the speed of the planets while Newton studied the forces that
nasty-shy [4]
Kepler did not study the speed of the planets, rather, he studied how the planets move in the solar system. He proposed three laws. As a summary, he described that the planets move around the sun in the shape of an ellipse (orbit), and the Sun being one of the foci. Then, he proposed the period for the planet to complete one revolution around the Sun. 

On the other hand, Newton studied the forces acting on the planet (or any object in space) that explain how the planets move around the solar system as described by Kepler. Also, Kepler's observations only apply to planets and not the moons or satellites. Thus, Kepler only made laws from observations, while Newton based it from underlying principles that led him to mathematical equations such as the law of universal gravitation.
4 0
3 years ago
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You are working in a lab when radiation alarms go off. You are able to hide inside a steel cabinet, whose sides are about 1.5 in
dusya [7]

Answer:

Its either B or C (in my opinion)

6 0
3 years ago
A hydrate of CoCl2 has a mass of 17.40 g before heating. After heating, the mass of the anhydrous compound is found to be 10.27
melisa1 [442]

Mass CoCl2 = 10.27 g
moles CoCl2 = 10.27 g/ 129.839 g/mol=0.07910

mass water = 17.40 - 10.27=7.13 g
moles water = 7.13 / 18.02 g/mol=0.396

0.396/ 0.07910=5

CoCl2 * 5 H2O

moles CaF2 = 85.8 g/ 78.0748 g/mol=1.10
moles Ca = 1.10
mass Ca = 1.10 x 40.078 g/mol=44.1 g
V = 44.1 / 1.55 =28.5 mL

Greetings!!
5 0
3 years ago
At what point does the radiation start to affect satellites in the atmosphere
Aleksandr-060686 [28]
After that have been up for a while thay are metal
6 0
2 years ago
How much heat is required to change 100 g of ice (H2O) at 253 K to vapor (steam) at 393 K?
soldier1979 [14.2K]

<u>Answer:</u> The heat required will be 58.604 kJ.

<u>Explanation: </u>

To calculate the amount of heat required, we use the formula:

Q= m\times c\times \Delta T

Q= heat gained  or absorbed = ? J

m = mass of the substance = 100 g

c = heat capacity of water = 4.186 J/g ° C

Putting values in above equation, we get:

\Delta T={\text{Change in temperature}}=(393-253)K=140K=140^oC

Q=100g\times 4.186J/g^oC\times 140^oC

Q = 58604 Joules  = 58.604 kJ     (Conversion factor: 1 kJ = 1000J)

Thus, heat released by 100 grams of ice is 58.604kJ.

3 0
3 years ago
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