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LUCKY_DIMON [66]
3 years ago
6

Determine whether each of the molecules below is polar or nonpolar. Tetrahedral C C l 4 CClX4 Nonpolar Tetrahedral C H 3 O H CHX

3OH Polar Trigonal pyramidal N H 3 NHX3 Nonpolar Linear C S 2 CSX2 Nonpolar
Chemistry
1 answer:
liraira [26]3 years ago
3 0

Answer:

CCl4 - Nonpolar

CH3OH - polar

NH3 - polar

CS2 - Nonpolar

Explanation:

One important thing that we should know is that polarity has to do with the presence of a resultant dipole moment in a molecule.

Dipole moment is a vector quantity, This means that its direction is also taken into account when discussing the dipole moment of molecules.

Hence, symmetrical molecules such as CS2 and CCl4 are non-polar even though they have polar bonds because their dipoles cancel out(zero resultant dipole moment).

On the other hand, NH3 and CH3OH are non-symmetrical molecules hence they possess an overall dipole moment and are polar molecules.

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The process, when an atom gains electrons is called
max2010maxim [7]

Answer:

When an atom gains/loses an electron, the atom becomes charged, and is called an ion. Gaining an electron results in a negative charge, so the atom is an anion. Losing an electron results in a positive charge, so atom ion is a cation

Explanation:

Answerd the question : ion

8 0
3 years ago
What is the concentration of ammonia in a solution if 23.4 mL of a 0.117 M solution of HCl are needed to titrate a 100.0 mL samp
Georgia [21]

Answer: 0.0274 M

Explanation:-

The balanced chemical solution is:

NH_4OH(aq)+HCl(aq)\rightarrow NH_4Cl(aq)+H_2O(l)

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HCl solution = 0.117 M

V_1 = volume of HCl solution = 23.4 ml

M_2 = molarity of NH_4OH solution = ?

V_2 = volume of NH_4OH solution = 100.0 ml

n_1 = valency of HCl = 1

n_2 = valency of NH_4OH = 1

1\times 0.117M\times 23.4=1\times M_2\times 100.0

M_2=0.0274

Therefore, the concentration of ammonia in a solution will be 0.0274 M

8 0
3 years ago
kiran lit a candle. she placed a 100cm glass jar over the candle. the candle flame went out after 2 seconds. why did the flame g
Radda [10]

Answer:

The candle took up all the oxygen under the glass

Explanation:

Carbon dioxide molecules are heavier than air. Because of this, they push the oxygen and other molecules in the air out of the way as they sink down over the flame and candle. When oxygen is pushed away from the wick, it can't react with the wax anymore.

4 0
4 years ago
CH4(g)+ 2 O2(g) + CO2(g) + 2 H20 (l)
jasenka [17]

Answer:

<u>∆H° reaction = -890.3 kJ</u>

Explanation:

The given equation is :

CH_{4}(g)+2O_{2}(g)\rightarrow CO_{2}(g)+2H_{2}O(l)

Now ,

O2 is in the standard state so its  ∆H° is zero.

∆H° is calculated by considering the formation of CO2 , H2O and CH4 .

C(s)+H_{2}(g)\rightarrow CO_{2}..........∆H°a = -393.5 kJ

H_{2}+\frac{1}{2}O_{2}\rightarrow H_{2}O(l).....∆H°b = -285.8 kJ

C+2H_{2}\rightarrow CH_{4}(g)..........∆H°c = -74.8 kJ

Multiply equation of water H2O by 2

and reverse the direction of equation of CH4

Hence the sign of ∆H°c = +74.8 kJ becomes +ve.

We are doing this because CH4 is to be in the reactant side not  in the product side.

∆H° reaction = ∆H°a +2(∆H°b) -∆H°c

∆H° reaction = -393.5 - 2(285.8) + 74.8

∆H° reaction = -890.3 kJ

4 0
3 years ago
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