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elixir [45]
3 years ago
5

What is the name of SbBr3

Chemistry
2 answers:
aniked [119]3 years ago
4 0

Answer: Antimonous bromide. Antimony bromide (SbBr3)

Description: Antimony tribromide is a yellow cr...

Synonyms: ANTIMONY TRIBROMIDE Antimon

Molecular Formula: SbBr3 or Br3Sb

Molecular Weight: 361.47 g/mol

Explanation:

gayaneshka [121]3 years ago
3 0
Antimony Tribromide is the answer
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Indica las condiciones que debe cumplir una colisión entre moléculas para que se produzca una reacción química
g100num [7]

Answer:

Las moléculas de los reactivos tienen que chocar entre sí. Estos choques deben de producirse con energía suficiente de forma que se puedan romper y formar enlaces químicos. En el choque debe haber una orientación adecuada para que los enlaces que se tienen que romper y formar estén a una distancia y posición viable.

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3 years ago
Discuss the different observations that you would record during an investigation into the energy transformations of a lamp that
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Answer:

See the answer below, please.

Explanation:

Take as an example a light bulb inside a lamp to illuminate a room. When you plug it in a plug and turn it on, light is generated. More precisely, heat (Joule effect) is produced inside the lamp by its internal filament (conductive material) when it passes through the electrical energy, generated by the friction of the atoms that are inside it when it encounters a resistance.

3 0
3 years ago
88.7 g of H2O = ? L help please
Hatshy [7]

Answer:

88.7 grams of water is equal to 0.0887 liters.

Explanation:

1000 grams of water is equal to 1 liter

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6 0
3 years ago
What BEST describes these three molecules?
Rzqust [24]
They are structural isomers
8 0
3 years ago
A metal object with mass of 22.7 g is heated to 97.0 ∘C and then transferred to an insulated container containing 84.7 g of wate
Lunna [17]

The specific heat of the metal object with a mass of 22.7g heated to to temperature of 97.0°C and then transferred to an insulated container containing 84.7 g of water at 20.5 ∘C is 0.815J/g°C

How to calculate specific heat?

The specific heat capacity of a metal can be calculated using the calorimetry equation as follows:

Q = mc∆T

Where;

Q = quantity of heat absorbed

m = mass of substance

c = specific heat capacity

∆T = change in temperature

mc∆T (water) = -mc∆T (metal)

84.7 × 4.18 × 3.8 = - (22.7 × c × -72.7)

1345.375 = 1650.29c

c = 0.815J/g°C

Therefore, the specific heat of the metal object with a mass of 22.7g heated to to temperature of 97.0°C and then transferred to an insulated container containing 84.7 g of water at 20.5 ∘C is 0.815J/g°C.

Learn more about specific heat capacity at:

#SPJ1

3 0
2 years ago
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