Answer:
%M = 16.2%
%N = 18.9%
%O = 64.9%
Explanation:
Mg(NO3)2
Atomic mass of Magnesium M = 24
Atomic mass of Nitrogen N=14
Atomic mass of Oxygen O=16
Molar mass of Mg(NO3)2 = 24 + (14+[16*3})*2
Mg(NO3)2 = 24 + (14+48)*2
Mg(NO3)2 = 24 + 124
Mg(NO3)2 = 148
Percentage composition;
Magnesium M= (24/148) × 100
Magnesium M=0.162 × 100 =16.2%
Oxygen O=(16*6/148) × 100
Oxygen O= 0.649 × 100 = 64.9%
Nitrogen N= (14*2/148) × 100
Nitrogen N=0.189 × 100=18.9%