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2 years ago

Calculate the percent composition of Mg(NO3)2.

Chemistry

1 answer:

dimaraw [331]2 years ago

3 0

Answer:

%M = 16.2%

%N = 18.9%

%O = 64.9%

Explanation:

Mg(NO3)2

Atomic mass of Magnesium M = 24

Atomic mass of Nitrogen N=14

Atomic mass of Oxygen O=16

Molar mass of Mg(NO3)2 = 24 + (14+[16*3})*2

Mg(NO3)2 = 24 + (14+48)*2

Mg(NO3)2 = 24 + 124

Mg(NO3)2 = 148

Percentage composition;

Magnesium M= (24/148) × 100

Magnesium M=0.162 × 100 =16.2%

Oxygen O=(16*6/148) × 100

Oxygen O= 0.649 × 100 = 64.9%

Nitrogen N= (14*2/148) × 100

Nitrogen N=0.189 × 100=18.9%

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