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3 years ago

How does a full octet affect trends among the noble gases?

Chemistry

2 answers:

shutvik [7]3 years ago

8 0

The answer is that a full octet makes the noble gases nonreactive. Hope this helps

Marianna [84]3 years ago

6 0

Full octet means all the noble gases have their octet full that is they have their valence shell full, there is no lacking of electron in the valence shell that can be received and there is no extra electron present in the valence shell that can be donated to another element. So that means noble gases are less reactive and more stable due to their full octet. So full octet makes noble gases less reactive and more stable.

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why can scientists ignore the forces of attraction between particles in a gas under ordinary conditions

Galina-37 [17]

The forces of attraction between particles in their gaseous state seems to be nonexistential.
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3 years ago

Which of the following is true about an atom of silver

kati45 [8]

Answer:

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Two Balloons one filled with hydrogen gas and second filled with neon gas. what gas should be used in an experiement to identify

dalvyx [7]

Answer:

Oxygen

Explanation:

If two balloons are filled with hydrogen gas and helium gas respectively, then we want to identify what gas is in each balloon, we have to do so by exposing the both balloons to flame in an oxygen atmosphere.

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The reason for the explosion of the gas in the hydrogen balloon is that combustion of hydrogen gas is exothermic. The heating up of surrounding air molecules leads to a sudden explosion.

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3 years ago

Balance the equation Ca(s) + H3PO4(aq) ---->Ca3(PO4)2(s) + H2(g)

vovikov84 [41]

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2 years ago

Two common methods to generate an aldehyde is by oxidation of an alcohol and through ozonolysis.

kotykmax [81]

Answer:

a. True.

Explanation:

Only primary and secondary alcohols can oxidise to give an aldehyde. But a weak oxidizing agent must be used to prevent formation of a carboxylic acid or ketone.

weak oxidizing agents: Chromyl chloride, silver/oxygen/500°C

take an example of ethanol:

 ${ \bf{CH _{3} CH_{2}OH \: \: \frac{Ag/O_{2} }{500 \degree C} > \: \:CH _{3} CHO}}$ 

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take an example of propanol:

if it undergoes ozonolysis, it gives ethanal and methanal.

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3 years ago

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