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german
3 years ago
7

How does a full octet affect trends among the noble gases?

Chemistry
2 answers:
shutvik [7]3 years ago
8 0
The answer is that a full octet makes the noble gases nonreactive. Hope this helps
Marianna [84]3 years ago
6 0

Full octet means all the noble gases have their octet full that is they have their valence shell full, there is no lacking of electron in the valence shell that can be received and there is no extra electron present in the valence shell that can be donated to another element. So that means noble gases are less reactive and more stable due to their full octet. So full octet makes noble gases less reactive and more stable.

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The highly reactive elements in group 7a are known for forming salts.what are they called
yaroslaw [1]
Group 7A are halogens 

If you look at a periodic table, these elements include F, Cl, Br, I, and At. Some well known salts are KCl and NaCl (better known as table salt!)
7 0
3 years ago
Calculate the number of grams of oxygen gas in a 24L container at STP
romanna [79]

There are 34 g of oxygen in the container.

We can use the<em> Ideal Gas Law</em> to solve this problem.

pV = nRT

But n = \frac{m}{M}, so

pV = \frac{m}{M}RT and

m = \frac{pVM}{RT}\\

STP is 0 °C and 1 bar, so

m = \frac{\text{1 bar} \times \text{24 L} \times 32.00 \text{ g}\cdot\text{mol}^{-1}}{\text{0.083 14 } \text{bar}\cdot\text{L}\cdot\text{K}^{-1}\text{mol}^{-1}\times\text{273.15 K} } = \textbf{34 g}\\

7 0
3 years ago
Compare the wavelength and energy of ultraviolet rays to visible light
Nadusha1986 [10]

Answer:

Visible wavelengths range from 0.0007 milimeters for red light, through orange, yellow, green, and blue, to 0.0004 milimeters for violet light.

Ultraviolet is shorter wavelengths than violet.

Hope This Helps.

6 0
3 years ago
Determine the mass of hydrogen contained in 9.06 x 1024 H2O molecules.
Elza [17]

Answer:

15.2 g H2

Explanation:

2H2O -> 2H2 + O2

9.06 x 10^24 molecules x (1 mol/6.022 x 10^23 molecules) x (2 mol H2/2 mol H2O) x (1.008 g/1 mol) = 15.2 g H2

4 0
2 years ago
What mass of potassium iodide is needed to prepare 5.60 L of a 1.13 M solution
MrMuchimi
Given that the question gives us concentration (M) and volume, we can use these so get moles. remember that Molarity (M)= mol/ Liters, so if we want the moles, then

moles= M x L

moles= 1.13 x 5.60= 6.33 moles KI

now to get the mass in grams, we need the molar mass of potassium iodide (KI) which can be determined using the periodic table and add the masses of each atom.

molar mass KI= 39.1 + 127= 166.1 g/mol

6.33 mol (166 g/ 1 mol)= 1050 grams KI


8 0
3 years ago
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