1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
german
3 years ago
7

How does a full octet affect trends among the noble gases?

Chemistry
2 answers:
shutvik [7]3 years ago
8 0
The answer is that a full octet makes the noble gases nonreactive. Hope this helps
Marianna [84]3 years ago
6 0

Full octet means all the noble gases have their octet full that is they have their valence shell full, there is no lacking of electron in the valence shell that can be received and there is no extra electron present in the valence shell that can be donated to another element. So that means noble gases are less reactive and more stable due to their full octet. So full octet makes noble gases less reactive and more stable.

You might be interested in
What is the purpose of writing Shorthand Electron Configuration Using Noble Gases?<br> 30 POINTS!
aivan3 [116]

The noble gas configuration system helps to shorten the total electron configuration by using the symbol for the noble gas that lies before the particular element in the periodic table.  

For example:

Na has atomic number 11

Electron configuration of Na: 1s2 2s2 2p6 3s1

Noble gas electron configuration of Na: [Ne] 3s1

Ne has atomic number 10 and lies before Na in the periodic table.  


6 0
3 years ago
How many atoms are in Ca(C2H3O2)2
irga5000 [103]
15 atoms. 

Hope this helped!
3 0
4 years ago
Read 2 more answers
A chemist can determine the mass of K in a sample of known mass that consists of either pure K2O or pure K2O2. From this informa
Arte-miy333 [17]

Yes , the chemist can answer if the compound in K2O or K2O2

The chemical formula and composition of both the compounds is entirely different. The compound K2O2 has an additional molecule of oxygen than K2O and hence will have have higher molecular mass.

In the compound K2O

molecular mass= 2x 39+16 =94

mass ratio of K in compound= 78/94 = 0.830

In the compound K2O2

molecular mass= 2x 39+16X2 =110

mass ratio of K in compound= 78/110 = 0.710

and hence by the required ratio while extracting K , the chemist may know if the compound is K20 or K2O2

If the ratio is anything different from 0.830 and 0.710 then the compund will be something different

#SPJ9

5 0
2 years ago
It didn't have science but it is a science question. The average, year-after-year conditions of temperature, precipitation, wind
larisa86 [58]
Hey there,

Question : <span>The average, year-after-year conditions of temperature, precipitation, winds, and cloud in an area are known as its?

Answer : A, climate

Hope this helps :))

<em>~Top♥</em>
</span>
6 0
4 years ago
Does any one understand dis
Orlov [11]
I understand it but the format doesn't make sense to me
5 0
4 years ago
Other questions:
  • What is the process where a liquid changes from its liquid state to a gaseous state?
    15·2 answers
  • 1.72 mol of LiCl in 37.5 L of solution
    9·1 answer
  • Examine the following unbalanced chemical equation: CO2 + C → CO. Which of the following is the correctly balanced form of this
    15·1 answer
  • Is this statement true or false? Oil and natural gas are fuel resources harvested from the ocean.
    14·2 answers
  • How has desertification impacted the environment in Latin America?
    10·1 answer
  • What cation ion is formed from magnesium iodate
    14·1 answer
  • What material would be safest to use as an insulator to cover electrical wires?
    14·2 answers
  • Saturated solution of an ionic compound has a
    10·1 answer
  • Calculate the maximum concentration (in m) of calcium ions (Ca2+ ) in a solution that contains of CO3^2-. The ksp of CaCO3 is?
    9·1 answer
  • what volume (in ml) of 1.508 m h3po4 (aq) would be required to react completely with 11.73 ml of 1.006 m ca(oh)2? (aq)
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!