Answer:
qualitative data
and
quanitative data
Explanation:
hope this helps and PLZ brainliest thank you
In such type of problems where reactant and product ratios are calculated one (Launa) should take start from balanced chemical equation. A balanced chemical equations helps in solving such problems. For this purpose chemical equation of this combustion reaction is drawn.
Equation:
C₃H₁₀ ⁺ 5 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 3 CO₂ ⁺ 4 H₂O
Now, According to this balanced equation one molecule of propane reacts with 5 molecules of oxygen to produce 3 molecules of carbon dioxide and 4 molecules of water.
As She is given with 2 molecules of propane and 10 molecules of oxygen, which means that the equation is multiplied by 2. So, the product side must also be multiplied by 2 to balance the equatio (Law of Conservation of Mass).
Result:
( C₃H₁₀ ⁺ 5 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 3 CO₂ ⁺ 4 H₂O ) ₓ 2
2 C₃H₁₀ ⁺ 10 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 6 CO₂ ⁺ 8 H₂O
So, 6 molecules of carbon dioxide and 8 molecules of water are produced.
Answer:
Answer:
<h2>1.75 x 10-4 M</h2>
Explanation:
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