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Brums [2.3K]
3 years ago
13

A moving company is called into a building and asked to relocate 520 bricks to a location 15 meters above the ground. If each br

ick is 4 kilograms, what amount of work will be needed to accomplish the task? A. 305,760 J B. 229,320 J C. 203,840 J D. 588,000 J
Chemistry
2 answers:
Blababa [14]3 years ago
3 0
Work = Force * distance (aka Weight * height lifted)

Work to lift 1 brick:
W = mgh = (4 kg)(9.8 m/s²)(15 m) = 588 J

Work to lift 520 bricks:
W = 520(588 J) = 305,760 J
Pepsi [2]3 years ago
3 0

I just took the test, the answer is A. 305,760 J, good luck.

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Write the empirical formula for at least four ionic compounds that could be formed from the following ions:
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The empirical formula of compounds formed from the given ions are as follows:

  • Pb⁴⁺ = PbO₂
  • NH₄⁺ = NH₄Cl
  • CrO₄²⁻ = Na₂CrO₄
  • SO₄²⁻ = K₂SO₄

<h3>What is the empirical formula of a compound?</h3>

The empirical formula of a compound is the simplest formula of the compound showing the simplest ratios in which elements in the compound combine.

The empirical formula of compounds formed from the given ions are as follows:

  • Pb⁴⁺ = PbO₂
  • NH₄⁺ = NH₄Cl
  • CrO₄²⁻ = Na₂CrO₄
  • SO₄²⁻ = K₂SO₄

In conclusion, the empirical formula is the simplest formula of a compound.

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Ñspent fuelî that can no longer be used to create energy.<br> nuclear waste ?
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Ch4+br2=ch3br+hbr which type of reaction does this equation represent
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100 POINTS! Final Honor Activity Question
castortr0y [4]

The change in temperature had the greatest effect at changing the volume of the balloon.

<h3>What are the gas laws?</h3>

The gas laws are used to describe the parameters that has to do with gases.

Given that;

P1 = 98.5 kPa

T1 = 18oC or 291 K

V1 =  74.0 dm3

P2 =  7.0 kPa

V2 = ?

T2 = 18oC or 291 K

P1V1/T1 = P2V2/T2

P1V1T2 =P2V2T1

V2= P1V1T2/P2T1

V2 =  98.5 kPa *  74.0 dm3 * 291 K/ 7.0 kPa * 291 K

V2 = 1041.3 dm3

When;

V1 = 1041.3 dm3

T1 = 291 K

V2 = ?

T2 = 80oC or 353 K

V1/T1 = V2/T2

V1T2 = V2T1

V2 = V1T2/T1

V2 = 1041.3 dm3 * 353 K/291 K

V2 = 1263 dm3

The change in temperature had the greatest effect at changing the volume of the balloon.

Given that

V1 =  100 cm^3

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P1 = 1.01 * 10^5 Pa

V2 = ?

P2 =  3.00 x 10^-4 Pa

T2 = -180oC or 255 K

V2= P1V1T2/P2T1

V2 =  1.01 * 10^5 Pa * 100 cm^3 * 255 K / 3.00 x 10^-4 Pa * 273 K

V2 = 3.14 * 10^10 cm^3

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