The single most important factor influencing potassium ion secretion is its concentration in blood plasma.
<h3>
What is Plasma?</h3>
This is the liquid portion of the blood and serves as the transport medium for nutrients in the body.
When there is a high concentration in the plasma, it maximizes the concentration gradient which favors its secretion into the urinary fluid.
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Option D: Chromium would require the most energy to convert one mole of gaseous atoms into gaseous ions each carrying two positive charges.
<h3>What does the term “ionization energy” mean? </h3>
The ionization energy measures an element’s ability for participating in any chemical processes that calls up for the creation of ions or the donation of other electrons.
It is defined as the energy that any electron present in a gaseous atom or ion has in order to absorb so that it comes out of the influence of the nucleus and hence freely move
Ionization energy is also said as the minimum energy required to remove the most loosely bound electron that is present in an isolated gaseous atom or a positive ion or a molecule.
It can be easily connected to the type of chemical bonds that exist between the components in the compounds that they form.
<h3>Which element ionizes most energetically?</h3>
Helium, because it has the highest first ionization energy, whereas francium has one of the lowest.
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Answer:
C. CH3COOH, Ka = 1.8 E-5
Explanation:
analyzing the pKa of the given acids:
∴ pKa = - Log Ka
A. pKa = - Log (1.0 E-3 ) = 3
B. pKa = - Log (2.9 E-4) = 3.54
C. pKa = - Log (1.8 E-5) = 4.745
D. pKa = - Log (4.0 E-6) = 5.397
E. pKa = - Log (2.3 E-9) = 8.638
We choose the (C) acid since its pKa close to the expected pH.
⇒ For a buffer solution formed from an acid and its respective salt, we have the equation Henderson-Hausselbach (H-H):
- pH = pKa + Log ([CH3COO-]/[CH3COOH])
∴ pH = 4.5
∴ pKa = 4.745
⇒ 4.5 = 4.745 + Log ([CH3COO-]/[CH3COOH])
⇒ - 0.245 = Log ([CH3COO-]/[CH3COOH])
⇒ 0.5692 = [CH3COO-]/[CH3COOH]
∴ Ka = 1.8 E-5 = ([H3O+].[CH3COO-])/[CH3COOH]
⇒ 1.8 E-5 = [H3O+](0.5692)
⇒ [H3O+] = 3.1623 E-5 M
⇒ pH = - Log ( 3.1623 E-5 ) = 4.5
