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Brums [2.3K]
3 years ago
13

A moving company is called into a building and asked to relocate 520 bricks to a location 15 meters above the ground. If each br

ick is 4 kilograms, what amount of work will be needed to accomplish the task? A. 305,760 J B. 229,320 J C. 203,840 J D. 588,000 J
Chemistry
2 answers:
Blababa [14]3 years ago
3 0
Work = Force * distance (aka Weight * height lifted)

Work to lift 1 brick:
W = mgh = (4 kg)(9.8 m/s²)(15 m) = 588 J

Work to lift 520 bricks:
W = 520(588 J) = 305,760 J
Pepsi [2]3 years ago
3 0

I just took the test, the answer is A. 305,760 J, good luck.

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The element copper has naturally occurring isotopes with mass numbers of 63 and 65. The relative abundance and atomic masses are
timofeeve [1]

Answer:

63.546

Explanation:

The Average atomic mass is calculated using the formula:

sum of the product of the atomic masses and their relative abundances all divided by 100 or total abundance

4 0
3 years ago
A weight of 22.25g was obtained when 10-mL of water at 27C was pipet to empty Erlenmeyer flask. What is the volume delivered by
Nimfa-mama [501]

Answer:

the volume delivered by the pipette = 22.32 mL

Explanation:

To calculate this, let us first note that the density of water relates it weight and its volume (density = mass ÷ volume), hence we are going to use density to determine the volume.

Density of water = mass/volume = 0.997 g/ mL

mass = 22.25g

Density = 0.997g/mL

volume = ?

density = \frac{mass}{volume}\\\therefore volume = \frac{mass}{density}\\volume = \frac{22.25}{0.997}\\volume =  22.32\ mL

∴ the volume delivered by the pipette = 22.32 mL

<em>Please note that this calculation is based on the fact that the weight of the empty flask has been determined and canceled out.</em>

4 0
3 years ago
A container initially holds 5.67 x 10^-2 mol of propane and has a volume of V1. The volume of the container was increased by add
Brut [27]

Answer:

Initial volume of the container (V1) = 1.27 L (Approx)

Explanation:

Given:

Number of mol (n1) = 5.67 x 10⁻²

Number of mol (n2) = (5.67 +2.95) x 10⁻² = 8.62 x 10⁻²

New volume (V2) = 1.93 L

Find:

Initial volume of the container (V1)

Computation:

Using Avogadro's law

V1 / n1 = V2 / n2

V1 / 5.67 x 10⁻² = 1.93 / 8.62 x 10⁻²

V1 = 10.9431 / 8.62

Initial volume of the container (V1) = 1.2695

Initial volume of the container (V1) = 1.27 L (Approx)

5 0
3 years ago
What stated of matter and how many phases are present when a 5.0 mL sample of oil is mixed with 100.0 mL of water?
tamaranim1 [39]
<h2>⇒</h2>

two layers of different liquids=two phases.

Because oil doesn't dissolve in water. It only floats on water.

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

7 0
3 years ago
What number do you never write as a coefficient?
N76 [4]

Answer:

When no coefficient is written in front of a formula it is assumed to be 1. 4. Numbers appearing in the formulas are known as subscripts. These can never be changed when balancing the equation or you will change the identity of the substance.

Explanation:

1. Reactants go on the left hand side and products go on the right hand side of a chemical equation. Be sure to write the correct formulas for the reactants and products.

· Remember atoms are conserved in a chemical reaction. ie they are neither created or destroyed. So all the atoms in the reactants must end up somewhere among the products.

2. Count the number of atoms of each element, compound or ion in the reactants and products. If they are not equal proceed further.

3. Balance the atoms one at a time by placing coefficients in front of the formula so that the numbers of atoms of each element are equal on both sides of the equation. Remember atoms may exist in an element, compound or ion.

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· Balance the atoms that occur in compounds before attempting to balance atoms that occur in elemental form. e.g. H2, O2 or Cl2

· To make it easier if a polyatomic ion appears unchanged on both sides of the equation treat it as a whole unit.

· When no coefficient is written in front of a formula it is assumed to be 1.

4. Numbers appearing in the formulas are known as subscripts. These can never be changed when balancing the equation or you will change the identity of the substance.

· Remember with subscripts, any number to the right of parentheses multiplies each subscript within the parentheses.

eg Fe2(SO4)3 contains 2 Fe atoms, 3 S atoms and 12 O atoms.

5. Finally make sure that all the coefficients are in the smallest possible whole number ratio.

4 0
3 years ago
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