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3 years ago

In a titration, 45.0 mL of KOH is neutralized by 75.0 mL of 0.30M HBr. How much KOH is in 1.0 liter of the KOH solution ?

1 answer:

8 0

KOH + HBr ---> KBr + H2O

0,3 moles of HBr ---in-------1000ml
x moles of HBr-------in------75ml
x = 0,0225 moles of HBr

according to the reaction: 1 mole of KOH = 1 mole of HBr
so
0,0225 moles of HBr = 0,0225 moles of KOH

0,0225 mole of KOH------in-----45ml
x moles of KOH -----------in------1000ml
x = 0,5 moles of KOH

answer: 0,5 mol/dm³ KOH (molarity)

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Two unknown compounds are analyzed. Compound I contain 5.63 g of tin and 3.37 g of chlorine, while compound II contains 2.5 g of

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Answer:

Compounds 1 and 2 are not the same

Explanation:

To solve this question we need to find the molecular formula of the compounds converting the mass of each atom to moles. Molecular formula is defined as the simplest whole number ratio of atoms present in a molecula:

Compound 1:

Moles Tin:

5.63g Sn * (1mol / 118.7g) = 0.04743 moles

Moles Cl:

3.37g Cl * (1mol / 35.45g) = 0.09506 moles

Ratio Cl:Sn

0.09506 moles / 0.04743 moles = 2

Molecular formula SnCl₂

Compound 2:

Moles Tin:

2.5g Sn * (1mol / 118.7g) = 0.02106 moles

Moles Cl:

2.98g Cl * (1mol / 35.45g) = 0.08406 moles

Ratio Cl:Sn

0.08406 moles / 0.02106 moles = 4

Molecular formula SnCl₄

Compounds 1 and 2 are not the same because molecular formulas are different.

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What is the potential energy of a 2-kg vase sitting on a table with a height of 1 meter?

lisov135 [29]

"20 J" is the "Potential Energy" of "vase" on the table.

Explanation:

The body possess some energy according to the position of the object that is the when an object is placed at a height it stores some energy it is called "Potential Energy".

Formula used to calculate the "Potential Energy" is $m\times g \times h$

Where, "m" is mass of vase is given that 2 kg, "g" is acceleration due to gravity is $10 m/s^2$ and "h" is height of the object where it placed is 1 m.

Substitute the given values in the formula,

Potential energy of the vase = $2\times10\times1$

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3 years ago

BONUS QUESTION

devlian [24]

Answer:

pH = 12.5

Explanation:

The reaction that takes place is

2OH⁻(aq) + Pb⁺²(aq) → Pb(OH)₂(s)

The OH⁻ species come from the metal hydroxide of the solution, and Pb(OH)₂ is the precipitate.

Now we convert 3.81 grams of Pb(OH)₂ into moles, using its molar mass:

3.81 g ÷ 241.12 g/mol = 0.0158 mol Pb(OH)₂

Now we convert 0.0158 Pb(OH)₂ moles into OH⁻ moles, using the stoichiometric coefficients of the reaction:

0.0158 mol Pb(OH)₂ * $\frac{2molOH^-}{1molPb(OH)_2}$ = 0.0316 mol OH⁻

With the given concentration (1 L), we calculate [OH⁻]:

[OH⁻] = 0.0316 mol / 1 L = 0.0316 M

Then we calculate the pOH of the solution:

pOH = - log[OH⁻] = 1.5

And finally we calculate the pH:

pH = 14 - pOH

pH = 12.5

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