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3 years ago

Plz help!!!!! Worth 15 points

Chemistry

1 answer:

ad-work [718]3 years ago

6 0

Answer: C. Europa Clipper

Explanation:

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Describe the structure of atoms including the masses, electrical, charges, and locations of protons, neutrons in the nucleus ,an

steposvetlana [31]

Answer:

The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge).

Explanation:

The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge).

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3 years ago

The product side of a chemical reaction is shown.

Inga [223]

The number that represents the coefficient on the product side of the chemical reaction, $-- > 7Ti_2(SO_4)_3$ is 7.

<h3>Coefficients of chemical equations</h3>

In equations representing chemical reactions, the coefficient of each reactant or product of a reaction is the number that comes on the left-hand side just before the chemical formula.

The coefficient of each species in a chemical reaction is obtainable when the equation of the reaction is balanced.

For example, in the following equation: 2A + B = 3C + D

The coefficients of A, B, C, and D are 2, 1, 3, and 1 respectively.

Applying this to the product side of a chemical reaction; $-- > 7Ti_2(SO_4)_3$

It means that the coefficient of the product is 7.

More on coefficients of chemical equations can be found here: brainly.com/question/28294176

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1 year ago

The use of thermite for welding produces an

Sveta_85 [38]

Answer:

C. grinding the reactants into finer grains

Explanation: I just took the assignment.

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3 years ago

The human body is composed of different systems made of specialized cells, tissues, and organs. Each of these structures has a s

kaheart [24]

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To eliminate waste. Think of Excrete being another word for remove!

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2 years ago

The standard cell potential (E°cell) for the reaction below is +1.10V. The cell potential for this reaction is ________ V when t

alexandr402 [8]

Answer: 0.94 V

Explanation:

For the given chemical reaction :

$Zn(s)+Cu^{2+}(aq)\rightarrow Cu(s)+Zn^{2+}$

Using Nernst equation :

$E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Cu^{2+}]}$

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = $298K$

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = +1.10 V

$E_{cell}$ = emf of the cell = ?

Now put all the given values in the above equation, we get:

$E_{cell}=+1.10-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{2.5}{1.0\times 10^{-5}}$

$E_{cell}=+1.10-0.16V=0.94V$

The cell potential for this reaction is 0.94 V

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3 years ago