Answer:
Mole fraction of nitrogen = 0.52
Explanation:
Given data:
Temperature = 31.2 °C
Pressure = 870.2 mmHg
Volume = 15.1 L
Mass of mixture = 24.1 g
Mole fraction of nitrogen = ?
Solution:
Pressure conversion:
870.2 /760 = 1.12 atm
Temperature conversion:
31.2 + 273 = 304.2 K
Total number of moles:
PV = nRT
n = PV/RT
n = 1.12 atm × 15.1 L / 0.0821 L.atm. mol⁻¹.K⁻¹ × 304.2 K
n = 16.9 L.atm. /25 L.atm. mol⁻¹
n = 0.676 mol
Number of moles of nitrogen are = x
Then the number of moles of CO₂ = 0.676 - x
Mass of nitrogen = x mol . 28 g/mol and for CO₂ Mass = 44 g/mol ( 0.676 - x)
24.1 = 28x + ( 29.7 -44x)
24.1 - 29.7 = 28x - 44x
-5.6 = -16 x
x = 0.35
Mole fraction of nitrogen:
Mole fraction of nitrogen = moles of nitrogen / total number of moles
Mole fraction of nitrogen = 0.35 mol / 0.676 mol
Mole fraction of nitrogen = 0.52
Answer:
Competition occurs when <em>(A) two or more organisms need the same resource.</em>
Explanation:
I dont think it could be (B), (C) or (D) because those don't really make sense.
Answer:
Br
Explanation:
Bromine atoms tend to gain just one electron to get to a full octet, as Bromine is in Group VII.
S<span>plit people in two groups of Casodex resistant treatment men (double -blind cross-over study) </span>
<span>50% get Casodex 50 mg ( BICALUTAMIDE 50 MG ) 1 tablet daily + 1 placebo tablet </span>
<span>Casodex is an anti testosterone agent. </span>
<span>50% get Casodex 50 mg 1 tablet daily + 1 Tamoxifen 20 mg tablet </span>
<span>Tamoxifen is an estrogen receptor inhibitor </span>
<span>Compare the results of tumor growth over 1 year's time then reverse the groups without the physician or the patient knowing if they are receiving tamoxifen or the placebo tamxoifen then compare tumor growth results again.</span>
The number of formula units in 2.50 mol of the compound is 15.1 * 10^23.
The question is unclear whether NaNO2 or NaNO3 is implied. However,in either case, the solution applies equally.
6.02 * 10^23 formula units of the compound are contained in 1 mole
x formula units are contained in 2.5 moles of the compound
x = 6.02 * 10^23 formula units * 2.5 moles/ 1 mole
x = 15.1 * 10^23 formula units of the compound.
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