If we had 79.3 grams of Xe, would we expect a volume that is
1 answer:
Answer:
13.44 liters of Xe
Explanation:
First, change grams to moles by dividing the mass given (79.3) by the mass of one mole of Xe (131.3) to get .6 moles.
Now you turn moles to liters (aka volume) by multiplying the number of moles of Xe (.6) by 22.4 to get 13.44 liters of Xe
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∆G = ∆H-T∆S
=20×10^3-(15+273)(.101×10^3)
=20000-(288)(101)
=20000-29088
=-9088 joule = -9.088 kj
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