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Vlada [557]
4 years ago
8

3 is less than or equal to 7+g

Mathematics
1 answer:
Fantom [35]4 years ago
6 0

2≤4 so you have to do that by seeing that 3 iss less that 7

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Please help me!!
zzz [600]
Alright
7) 5.5
9) 4.6666666666666666… 7
6) 3.75
10) 7.75
14) 135.41

5 0
2 years ago
If 2x+y=8 and x-y=1 then y=?
lesantik [10]
Hope this helps you.::

4 0
4 years ago
SDRTYUK243567Iaqwertyh.
JulijaS [17]

Answer

B, i think

Step-by-step explanation:

7 0
4 years ago
Please help with these partial fractions!!!
VARVARA [1.3K]

a. Factorize the denominator:

\dfrac{x+14}{x^2-2x-8}=\dfrac{x+14}{(x-4)(x+2)}

Then we're looking for a,b such that

\dfrac{x+14}{x^2-2x-8}=\dfrac a{x-4}+\dfrac b{x+2}

\implies x+14=a(x+2)+b(x-4)

If x=4, then 18=6a\implies a=3; if x=-2, then 12=-6b\implies b=-2. So we have

\dfrac{x+14}{x^2-2x-8}=\dfrac3{x-4}-\dfrac2{x+2}

as required.

b. Same setup as in (a):

\dfrac{-3x^2+5x+6}{x^3+x^2}=\dfrac{-3x^2+5x+6}{x^2(x+1)}

We want to find a,b,c such that

\dfrac{-3x^2+5x+6}{x^2(x+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac c{x+1}

Quick aside: for the second term, since the denominator has degree 2, we should be looking for another constant b' such that the numerator of the second term is b'x+b. We always want the polynomial in the numerator to have degree 1 less than the degree of the denominator. But we would end up determining b'=0 anyway.

\implies-3x^2+5x+6=ax(x+1)+b(x+1)+cx^2

If x=0, then b=6; if x=-1, then c=-2. Expanding everything on the right then gives

-3x^2+5x+6=ax^2+ax+bx+b+cx^2=(a-2)x^2+(a+6)x+6

which tells us a-2=-3 and a+6=5; in both cases, we get a=-1. Then

\dfrac{-3x^2+5x+6}{x^2(x+1)}=-\dfrac1x+\dfrac6{x^2}-\dfrac2{x+1}

as required.

5 0
4 years ago
A newborn kitten weighs 3 ounces at birth. After four weeks, it weighs 13 ounces. Which of the following is true?
notsponge [240]

Answer:

C cuz the propotional increases over time

Step-by-step explanation:

Easy just think of it as 30 and 3

5 0
3 years ago
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