The acceleration of the object after 3 seconds of fall is -9.8 m/s².
The given parameters;
- initial velocity of the object, u = 0
- time of motion of the object, t = 3 seconds
Acceleration is the change in velocity per change in time of motion.
The acceleration of the object after 3 seconds of fall is calculated as follows;
- Since the object is in free fall, the object experiences only acceleration due to gravity.
- the magnitude of this acceleration due to gravity is 9.8 m/s²
- the direction of this acceleration is downwards
Thus, the acceleration of the object after 3 seconds of fall is -9.8 m/s².
Learn more here: brainly.com/question/13197713
Answer:
Explanation:
Given that
Intensity I
Radius of earth,R = 6370 Km
We know that surface area of earth, A
As we know that pressure due to intensity given as
V =Velocity of light
We know that force F
F = P .A
b)Gravitational force F
So F
:<span> </span><span>Under the assumption that a cell is made up of two concentric spheres you find the surface are of the inside sphere which will be your A.
You already have your separation and dielectric constant so just use the formula you stated towards the end of your question and you get 8.93x10^-11 Farads which is about 89pF</span>
Answer:
Astronomers like to call all material made up of protons, neutrons and electrons "baryonic matter". Until about thirty years ago, astronomers thought that the universe was composed almost entirely of this "baryonic matter", ordinary atoms.
Explanation:
Answer:
In a two particle system, the center of mass lies on the center of the line joining the two particles.
