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Marta_Voda [28]
3 years ago
7

For a freely falling object dropped from rest, what is the acceleration at the

Physics
1 answer:
Zinaida [17]3 years ago
7 0

The acceleration of the object after 3 seconds of fall is -9.8 m/s².

The given parameters;

  • initial velocity of the object, u = 0
  • time of motion of the object, t = 3 seconds

Acceleration is the change in velocity per change in time of motion.

The acceleration of the object after 3 seconds of fall is calculated as follows;

  • Since the object is in free fall, the object experiences only acceleration due to gravity.
  • the magnitude of this acceleration due to gravity is 9.8 m/s²
  • the direction of this acceleration is downwards

 

Thus, the acceleration of the object after 3 seconds of fall is -9.8 m/s².

Learn more here: brainly.com/question/13197713

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1. A force of 25.0 Newtons is applied so as to move a 5.0 kg mass a distance of 20.0 meters. How much work was done?
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4. A rubber stopper, which has a mass of 38.0 grams, is being swung in a horizontal circle which has a radius of R = 1.35 meters. The rubber stopper is measured to complete 10 revolutions in 8.25 seconds.
a. What is the speed of the rubber stopper?
Ans. v =  v = •  v = .•(. ) v = 10.29 m/s .
b. How much force must be applied to the string in order to keep this stopper moving in this circular path at a constant speed?
Ans. The Centripetal Force, Fc = • = . • (. /)= 29.76 N .
c. How far will the stopper move during a period of 25.0 seconds?
Ans. d = vt = 10.29 m/s25 s = 257.25 m
d. How much work is done on the stopper by the force applied by the string during 25.0 seconds?
Ans. 0 J. The force is towards the center and the distance is around the perimeter of the circle. They are at right angles to each other. For work to be done, the force has to be in the same direction as the displacement.
5. How much work would be required to lift a 12.0 kg mass up onto a table 1.15 meters high?
Ans. W = F• d = mg d = 12 kg  9.8 m/s2  1.15 m = 135.24 J
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