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Marta_Voda [28]
3 years ago
7

For a freely falling object dropped from rest, what is the acceleration at the

Physics
1 answer:
Zinaida [17]3 years ago
7 0

The acceleration of the object after 3 seconds of fall is -9.8 m/s².

The given parameters;

  • initial velocity of the object, u = 0
  • time of motion of the object, t = 3 seconds

Acceleration is the change in velocity per change in time of motion.

The acceleration of the object after 3 seconds of fall is calculated as follows;

  • Since the object is in free fall, the object experiences only acceleration due to gravity.
  • the magnitude of this acceleration due to gravity is 9.8 m/s²
  • the direction of this acceleration is downwards

 

Thus, the acceleration of the object after 3 seconds of fall is -9.8 m/s².

Learn more here: brainly.com/question/13197713

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Answer:

decline

Explanation:

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Answer:

The steps are outlined in the explanation below.

Explanation:

The average velocity is derived midpoint from the initial to the final velocity. Here is the proof:

Find the total displacement:

let the displacement be given by the letter s

Then since the average velocity is defined as:  v_{av}  = \frac{x - x_{0} }{t - t_{0} }

where t = final time

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where x denotes the position, then

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3 years ago
Which of the following statements is accurate?
Volgvan

Answer: B. If an object's velocity is changing,it's either experiencing acceleration or deceleration.


Acceleration is defined as the rate at which an object changes its velocity. This implies that if an object is changing it's velocity it is experiencing acceleration/ deceleration.

Acceleration is a vector quantity that has both a magnitude and time.

It is represented as

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The SI unit for acceleration is m/s^2

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Answer:

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Explanation:

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Answer:

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