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iris [78.8K]
3 years ago
5

Rewrite the statement in ïf then statement΅and find a counterexample if false,

Mathematics
1 answer:
ipn [44]3 years ago
4 0

Answer:

If numbers divisible by 6 are also divisible by 3 then any thing times 6 will be the same by 3.

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What is the solution to this system of equations<br>(5z +y=2<br>( 47 +y=5​
prisoha [69]

Answer:

Z = 8.8 Y = - 42

Step-by-step explanation:

Y = 2 - 5Z

Y = 5 - 47

2 - 5Z = 5 - 47

- 5Z = - 44

5Z = 44

Z = 8.8

Y = 2 - 5 (8.8)

Y = 2 - 44

Y = - 41

Y = 5 - 47

Y = - 42

5 0
3 years ago
MARKING YOU BRAINLIST AND 5 STARS! A tire from Karen's car is shown below. Which is the closest to the distance traveled, in fee
Yuki888 [10]

Answer:

18.86 feet

Step-by-step explanation:

One rotation of the tire is equal to the circumference of the tire

The formula for circumference of a circle (remember that a tire is shaped as a circle) = πd

where

π = 22/7

d = diameter

The size of one revolution = 2 x 22/7 = 44/7 feet

The distance covered in one rotation of the tire is 44/7 feet

The distance covered in 3 rotations = (44/7) x 3 = 18.86 feet

3 0
2 years ago
Consider the statement "2 is a factor of n2 + 3n."
deff fn [24]

Answer:

The answer is the last one:

4 , 10 , 18 , (k + 1)² + 3(k + 1) and k² + 5k + 4

Step-by-step explanation:

∵ 2 is a factor of n² + 3n

∵ n = 1 ⇒ ∴ (1)² + 3(1) = 1 + 3 = 4 ⇒ 2 is a factor of 4

∵ n = 2 ⇒ ∴ (2)² + 3(2) = 4 + 6 = 10 ⇒ 2 is a factor of 10

∵ n = 3 ⇒ ∴ (3)² + 3(3) = 9 + 9 = 18 ⇒ 2 is a factor of 18

∵ n = k + 1 ⇒ ∴ (k + 1)² + 3(k + 1) ⇒ before the simplify

∵ n = k + 1 ⇒ ∴ k² + 2k + 1 + 3k + 3 = k² + 5k + 4 ⇒ after simplify

5 0
3 years ago
Three hundred high school seniors were surveyed about their intended college majors. The results are displayed in the Venn Diagr
atroni [7]

Answer: \frac{1}{10}

Step-by-step explanation:

Since, The total number of student = 300

Out of which,

The number of students who are only in Maths  = 120

And, The number of students who are only in Science  = 50

While, the students who are not from any subject = 100

Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None

= 300 - 120 - 50 - 100

= 30

That is, there are 30 students who are both from science and maths,

Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10

3 0
3 years ago
Read 2 more answers
Simplify
weeeeeb [17]
The answer is A !! Did it step by step , don’t forget to put a brainliest if you can ;)

3 0
3 years ago
Read 2 more answers
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