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Marina CMI [18]
3 years ago
13

I NEED THESE ANSWERS ASAP

Chemistry
1 answer:
Snezhnost [94]3 years ago
7 0
First one - Mg(OH)2+2HCl— MgCl2+ 2H2O
second one - CH4+2O2– 2H20
Third- is already balanced.
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2. Calculate the mass of 3.47x1023 gold atoms.
lapo4ka [179]

3.47 x 10^{23} atoms of gold have mass of 113.44 grams.

Explanation:

Data given:

number of atoms of gold = 3.47 x 10^{23}

mass of the gold in given number of atoms = ?

atomic mass of gold =196.96 grams/mole

Avagadro's number = 6.022 X 10^{23}

from the relation,

1 mole of element contains 6.022 x 10^{23} atoms.

so no of moles of gold given = \frac{3.47 X 10^{23}  }{6.022 X 10^{23} }

0.57 moles of gold.

from the relation:

number of moles = \frac{mass}{atomic mass of 1 mole}

rearranging the equation,

mass = number of moles x atomic mass

mass = 0.57 x 196.96

mass = 113.44 grams

thus, 3.47 x 10^{23} atoms of gold have mass of 113.44 grams

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What did you observe about the properties of the sodium carbonate mixture before the substances were mixed together?
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Would you consider adding a sodium carbonate solution to a magnesium sulfate .

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??

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