How many moles of gold are Cleveland to 1.204×1024 atoms
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So your answer would pretty much be 2.80 x 10^24. The picture is just the explanation and how you would get that answer.
Im taking lambda as x (wavelength)
m = 0.17 kg
v=37m/s
h=6.62*10^-34m²kg/s
x= h/mv
m = 0.17 kg
v=37m/s
h=6.62*10^-34m²kg/s
x= h/mv