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ollegr [7]
3 years ago
9

How many moles of gold are Cleveland to 1.204×1024 atoms

Chemistry
1 answer:
Whitepunk [10]3 years ago
4 0

Answer:

10

Explanation:

ye

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Que es la lluvia acida?​
givi [52]

Answer:

sour

Explanation:

8 0
3 years ago
15.0 g of Fe and 25.0 g of sand are added to 250.0 g of water. a. Determine the percent mass of Fe, sand, and water in the mixtu
lana [24]

Answer:

A. percentage mass of iron = 5.17%

percentage mass of sand  = 8.62%

percentage mass of water = 86.205%

B. (Iron + sand + water) -------> ( iron + sand) ------> sand

C. The step of separation of iron and sand

Explanation:

A. Percentage mass of the mixtures:

Total mass of mixture = (15.0 + 25.0 + 250.0) g =290.0 g

percentage mass of iron = 15/290 * 100% = 5.17%

percentage mass of sand = 25/290 * 100% = 8.62%

percentage mass of water = 250/290 * 100% = 86.205%

B. Flow chart of separation procedure

(Iron + sand + water) -------> separation by filtration using filter paper and funnel to remove water --------> ( iron + sand) -----------> separation using magnet to remove iron ------> sand

C. The step of separation of iron and sand by magnetization of iron will have the highest amount of error because during the process, some iron particles may not readily be attracted to the magnet as they may have become interlaced in-between sand grains. Also, some sand particle may also be attracted to the magnet as they are are borne on iron particles.

5 0
3 years ago
Find the partial pressure of helium gas in mmHg
mezya [45]

Answer:

214 mmhg

Explanation:

5 0
2 years ago
The smallest ionic radius among the following. <br> Li<br> Mg<br> Na+<br> be+
dimaraw [331]
The correct answer is Be+

That is because it lost a single electron but still has the same number of protons, and thus the effective charge attracting each electron is greater, which in turn makes the radius even smaller
5 0
3 years ago
15 mL of a 0.16 M solution of glucose was diluted until the total volume reached 95 mL. What is the concentration of new solutio
Nana76 [90]

Answer:

the concentration of new solution = 0.025 M

Explanation:

Given that :

The initial volume V_1 = 15 mL

Initial concentration M_1 = 0.16 M

Final volume V_2 = 95 mL

Final concentration M_2 = ???

We know that M_1 × V_1 = M_2V_2

Making M_2 the subject of the formulae; we have :

M_2 = (M_1 × V_1)/V_2

M_2 = (0.16 × 15)/ 95

M_2 = 0.025 M

Thus, the concentration of new solution = 0.025 M

3 0
3 years ago
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