Wavelength= v/f
v=c
3x10^8/8x10^14
3.8X10^-7
C
Answer:
The correct option is;
The sports car, because it has less mass and therefore less inertia
Explanation:
Newton's first law of motion states that an object will continue in its state of rest or uniform motion in a straight line unless acted on by a force. The property exhibited by the object is known as inertia
Newton's second law states that force is directly proportional to the rate of change of momentum produced
The rate of change of momentum of an object is directly proportional to the resultant force applied and is in the direction of the resultant force. The resultant force is equal to the rate of change of momentum.
Therefore, we have;
F = m·dv/dt = m×a
Given that the force required to move an object is directly proportional to its mass therefore, the inertia or the object resistance that requires a force to bring change is directly proportional to the mass of the object.
The mass of a sports car being considered lesser than the mass of the minivan will require less force to push and therefore has less inertia.
<span>This question is based on conservation of energy as the work done would lead to change in kinetice energy of car
change in KE = 1/2 mv(f)^2 - 1/2mv(i)^2 = 1/2m(v(f)^2-v(i)^2)
where v(f) and v(i) are the final and initial speeds
change in KE = 185kJ = 185,000J = 1/2 m((28m/s)^2-(23m/s)^2)
185,000=1/2 m(255m^2/s^2)
solving for m
m=1451kg</span>
Answer:
I think 90 w I am not sure but I think it is right
I hope it is helpful for u
Answer:
Explanation:
Given
Electric Field 
velocity 
mass of electron 
Force on a charge Particle moving in Magnetic Field
![F=e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]](https://tex.z-dn.net/?f=F%3De%5Cleft%20%5B%20%5Cvec%7BE%7D%2B%5Cleft%20%28%20%5Cvec%7Bv%7D%5Ctimes%20%5Cvec%7BB%7D%5Cright%20%29%5Cright%20%5D)
![a=\frac{e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]}{m}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Be%5Cleft%20%5B%20%5Cvec%7BE%7D%2B%5Cleft%20%28%20%5Cvec%7Bv%7D%5Ctimes%20%5Cvec%7BB%7D%5Cright%20%29%5Cright%20%5D%7D%7Bm%7D)
![a=\frac{1.6\times 10^{-19}\left [ 2\hat{i}+5.4\hat{j}+\left ( 8\hat{i}\times 0.4\hat{k}\right )\right ]}{9.1\times 10^{-31}}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B1.6%5Ctimes%2010%5E%7B-19%7D%5Cleft%20%5B%202%5Chat%7Bi%7D%2B5.4%5Chat%7Bj%7D%2B%5Cleft%20%28%208%5Chat%7Bi%7D%5Ctimes%200.4%5Chat%7Bk%7D%5Cright%20%29%5Cright%20%5D%7D%7B9.1%5Ctimes%2010%5E%7B-31%7D%7D)
