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3 years ago

What are the chemical properties of water?

2 answers:

7 0

It is form in acid base reaction. Water produce OH- ion and H+ ion. Hydrogen ion is then combine with a cation ion(positive) and anion ion(negative) to produce water . Hope it helps.

Bezzdna [24]3 years ago

6 0

It's a compound of hydrogen and oxygen

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Menthol, which is present in mentholated cough drops, is an organic compound

Pie

Answer:

The empirical formula is C10H20O

Explanation:

Step 1: Data given

Mass of the sample = 0.2010 grams

Mass of CO2 = 0.5658 grams

Molar mass CO2 = 44.01 g/mol

Mass of H2O = 0.2318 grams

Molar mass H2O = 18.02 g/mol

Atomic mass C = 12.01 g/mol

Atomic mass O = 16.0 g/mol

Atomic mass H = 1.01 g/mol

Step 2: calculate moles CO2

Moles CO2 = 0.5658 gram / 44.01 g/mol

Moles CO2 = 0.01286 moles

Step 3: Calculate moles C

For 1 mol CO2 we have 1 mol C

For 0.01286 moles CO2 we have 0.01286 moles C

Step 4: Calculate mass C

MAss C = 0.01286 moles * 12.01 g/mol

Mass C =0.1544 grams

Step 5: Calculate moles H2O

Moles H2O =0.2318 grams / 18.02 g/mol

Moles H2O = 0.01286 moles

Step 6: Calculate moles H

For 1 mol H2O we have 2 moles H

For 0.01286 moles H2O we have 2*0.01286 = 0.02572 moles H

Step 7: Calculate mass H

Mass H = 0.02572 moles * 1.01 g/mol

Mass H = 0.0260 grams

Step8: Calculate mass O

Mass O = 0.2010 - 0.1544 - 0.0260

Mass O = 0.0206 grams

Step 9: Calculate moles O

Moles O = 0.0206 grams / 16.0 g/mol

Moles O = 0.00129 moles

Step 10: Calculate the mol ratio

We divide by the smallest amount of moles

C: 0.01286 moles / 0.00129 moles = 10

H: 0.02572 moles / 0.00129 moles = 20

O: 0.00129 moles / 0.00129 moles = 1

The empirical formula is C10H20O

4 0

3 years ago

Read 2 more answers

As with any drug, aspirin (acetylsalicylic acid) must remain in the bloodstream long enough to be effective. Assume that the rem

Olenka [21]

Answer:

180 mg

Explanation:

For a first-order reaction, we can calculate the amount of aspirine (A) at a certain time (t) using the following expression.

$A=A_{0}.e^{-k.t}$

where,

k: rate constant

A₀: initial amount

If we know the half-life ( $t_{1/2}$ ) we can calculate the rate constant.

$k=\frac{ln2}{t_{1/2}} =\frac{ln2}{3h} =0.2h^{-1}$

When t = 4 h and A₀ = 400 mg, A is:

$A=400mg.e^{-0.2h^{-1}\times 4h} =180mg$

4 0

3 years ago

A certain half-reaction has a standard reduction potential +0.80 V . An engineer proposes using this half-reaction at the anode

Strike441 [17]

Answer:

a. Minimum 1.70 V

b. There is no maximum.

Explanation:

We can solve this question by remembering that the cell potential is given by the formula

ε⁰ cell = ε⁰ reduction - ε⁰ oxidation

Now the problem states the cell must provide at least 0.9 V and that the reduction potential of the oxidized species 0.80 V, thus

ε⁰ reduction - ε⁰ oxidation ≥ ε⁰ cell

Since ε⁰ oxidation is by definition the negative of ε⁰ reduction , we have

ε⁰ reduction - ( 0.80 V ) ≥ 0.90 V

⇒ ε⁰ reduction ≥ 1.70 V

Therefore,

(a) The minimum standard reduction potential is 1.70 V

(b) There is no maximum standard reduction potential since it is stated in the question that we want to have a cell that provides at leat 0.9 V

8 0

3 years ago

Please help me with

kkurt [141]

Answer:

which one?

Explanation:

5 0

3 years ago

What is the pressure if 0.567 moles of gas occupy 4.5 liters at a temperature of 300.0 K?

kakasveta [241]

The answer is D. Use the equation PV=nRT
P=(.567mol)(.0821)(300K)/4.5L

3 0

3 years ago