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Gnesinka [82]
2 years ago
13

Select the correct answer. Which statement best describes how chemical equations demonstrate conservation of mass? O A. The numb

er of reactants is the same as the number of products. O B. The compounds are the same on each side of the reaction. O c. The number of atoms of each element is the same on each side of the equation. OD. The state of matter is the same on each side of the equation.
Note:
No need to explain.​
Chemistry
2 answers:
skad [1K]2 years ago
8 0

Answer:

Option D

Hope it helps you

noname [10]2 years ago
7 0

Answer:

Option C )The number of atoms of each element is the same on each side of the equation.

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3. When the hydronium ion concentration of a solution is 1x10-4 M, What
rewona [7]

Answer:

pH = 4

Solution is acidic

Explanation:

Given data;

Hydronium ion concentration = 1 × 10⁻⁴ M

pH of solution = ?

Solution:

pH = -log [H₃O⁺]

pH = -log [ 1 × 10⁻⁴ ]

pH =  4

According to pH scale the pH 7 is neutral while the pH less than 7 is acidic and greater than 7 is basic. The given solution has pH 4 it means solution is acidic.

7 0
2 years ago
For the following reaction, 6.94 grams of water are mixed with excess sulfur dioxide . Assume that the percent yield of sulfurou
Alexxx [7]
<h3>Answer:</h3>

#a. Theoretical yield = 31.6 g

#b. Actual yield = 25.72 g

<h3>Explanation:</h3>

The equation for the reaction between sulfur dioxide and water to form sulfurous acid is given by the equation;

SO₂(g) + H₂O(l) → H₂SO₃(aq)

The percent yield of H₂SO₃ is 81.4%

Mass of water that reacted is 6.94 g

#a. To get the theoretical yield of H₂SO₃ we need to follow the following steps

Step 1: Calculate the moles of water

Molar mass of water = 18.02 g/mol

Mass of water = 6.94 g

But, moles = Mass/molar mass

Moles of water = 6.94 g ÷ 18.02 g/mol

                        = 0.385 mol

Step 2: Calculate moles of H₂SO₃

From the equation, the mole ratio of water to H₂SO₃ is 1 : 1

Therefore, moles of water = moles of H₂SO₃

Hence, moles of H₂SO₃ = 0.385 mol

Step 3: Theoretical mass of H₂SO₃

Mass = moles × Molar mass

Molar mass of H₂SO₃ = 82.08 g/mol

Number of moles of H₂SO₃ = 0.385 mol

Therefore;

Theoretical mass of H₂SO₃ = 0.385 mol ×  82.08 g/mol

                                             = 31.60 g

Thus, the theoretical yield of H₂SO₃ is 31.6 g

<h3>#b. Calculating the actual yield</h3>

We need to calculate the actual yield

Percent yield of H₂SO₃ is 81.4%

Theoretical yield is 31.60 g

But; Percent yield = (Actual yield/theoretical yield)×100

Therefore;

Actual yield = Percent yield × theoretical yield)÷ 100

                   = (81.4 % × 31.6) ÷ 100

                  = 25.72 g

The percent yield of H₂SO₃ is 25.72 g

6 0
3 years ago
The balanced chemical equation for the combustion of butane is: 2C2H2 + 5O2 CO2 + 2H2O 2CH4 + 5O2 2CO2 + 4H2O 2C4H10 + 13O2 8CO2
SCORPION-xisa [38]
Butane is C₄H₁₀.

C_4H_{10} + O_2 \to CO_2 + H_2O \\ \\&#10;\hbox{balance carbon and hydrogen on the right-hand side:} \\&#10;C_4 H_{10} + O_2 \to 4 \ CO_2 + 5 \ H_2O \\ \\&#10;\hbox{balance oxygen on the left-hand side:} \\&#10;C_4 H_{10} + \frac{13}{2} \ O_2 \to 4 \ CO_2 + 5 \ H_2O \\ \\&#10;\hbox{multiply by 2 to get rid of the fraction:} \\&#10;2 \ C_4H_{10} + 13 \ O_2 \to 8 \ CO_2 + 10 \ H_2O

The balanced equation is 2 C₄H₁₀ + 13 O₂ <span>→</span> 8 CO₂ + 10 H₂O.
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Which of these processes are chemical reactions?
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Rotting vegetables is a chemical change I think.
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