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3 years ago

A 42 kg object is 2.5 m from a 55kg object. How much is the force of attraction between them?

Physics

1 answer:

melisa1 [442]3 years ago

8 0

Answer:

Force of attraction is 2,46*10^-8N $F= G*(m1*m2/r^2)\\where \\\\G=6,67*10^-11 (N*m^2/kg^2)\\m1=42kg\\m2=55kg\\r=2,5m\\therefore\\F=6,67*10^-11*(42*55/2.5^2)\\ F=2,46*10^-8 N$

Explanation:

Using the Law of Universal Gravitation, proposed by Newton.

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3 years ago

If something weighs 2891N on earth, what’s it’s mass?

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2 years ago

An egg is thrown nearly vertically upward from a point near the cornice of a tall building. The egg just misses the cornice on t

diamong [38]

Answer:

1. 18.5m/s

2. 17.5 m

3. 0 at its highest point

4. Direction is downwards

Explanation:

1. This egg is thrown vertically from a height

Yo = 0. This egg then falls to the point y = -30.0 at t = 5seconds

Y-Yo = V0t - 1/2gt²

-30-0 = V0(5)-1/2(9.8)(5²)

-30 = 5v0 - 4.9x25

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-30+122.4 = 5v0

V0 = 92.5/5

= 18.5m/s

this is the initial speed of the egg

2. When the egg is at a maximum height it would have a velocity equal to 0

V² = V0² - 2*g*y

V = 0, V0 = 18.5, g = 9.8

0 = 18.5²-2x9.8*y

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342.25 = 19.6y

Divide through by 19.6

Y = 342.25/19.6

Y = 17.5m

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5. Please check attachment for graph

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