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Nutka1998 [239]
3 years ago
14

A 42 kg object is 2.5 m from a 55kg object. How much is the force of attraction between them?

Physics
1 answer:
melisa1 [442]3 years ago
8 0

Answer:

Force of attraction is 2,46*10^-8NF= G*(m1*m2/r^2)\\where \\\\G=6,67*10^-11 (N*m^2/kg^2)\\m1=42kg\\m2=55kg\\r=2,5m\\therefore\\F=6,67*10^-11*(42*55/2.5^2)\\ F=2,46*10^-8 N

Explanation:

Using the Law of Universal Gravitation, proposed by Newton.

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It is a misconception that theories turn into laws with enough research.

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Are photons causing the electrons to flow off of the target? ( the target is calcium)
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Answer:

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Explanation:

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3 years ago
Which of the following describes the products of a chemical reaction? A. The original materials B. The substances that are chang
lianna [129]

The products of a chemical reaction are the substances that are changed and the chemicals on the right side of a chemical equation. The correct options are B and C.

<h3>What is chemical reaction?</h3>

The chemical reaction  is the reaction between two reactants which led to the formation of products.

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7 0
2 years ago
A 500kg car skids to a stop at a traffic light, leaving behind a 18.25m skid mark as it comes to a rest. Assuming that the car i
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Answer:

Coefficient of friction will be 0.587

Explanation:

We have given mass of the car m = 500 kg

Distance s = 18.25 m

Initial velocity of the car u = 14.5 m/sec

As the car finally stops so final velocity v = 0 m/sec

From second equation of motion

v^2=u^2+2as

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a=-5.76m/sec^2

We know that acceleration is given by

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5.76=\mu\times  9.81

\mu =0.587

So coefficient of friction will be 0.587

6 0
4 years ago
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