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Nutka1998 [239]
3 years ago
14

A 42 kg object is 2.5 m from a 55kg object. How much is the force of attraction between them?

Physics
1 answer:
melisa1 [442]3 years ago
8 0

Answer:

Force of attraction is 2,46*10^-8NF= G*(m1*m2/r^2)\\where \\\\G=6,67*10^-11 (N*m^2/kg^2)\\m1=42kg\\m2=55kg\\r=2,5m\\therefore\\F=6,67*10^-11*(42*55/2.5^2)\\ F=2,46*10^-8 N

Explanation:

Using the Law of Universal Gravitation, proposed by Newton.

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A cube has a density of 1900 kg/m 3 kg/m3 while at rest in the laboratory. What is the cube's density as measured by an experime
Deffense [45]

Answer:

4847.94844926 kg/m³

Explanation:

\rho' = Actual density of cube = 1900 kg/m³

\rho = Density change due to motion

v = Velocity of cube = 0.92c

c = Speed of light = 3\times 10^8\ m/s

Relativistic density is given by

\rho=\dfrac{\rho'}{\sqrt{1-\dfrac{v^2}{c^2}}}\\\Rightarrow \rho=\dfrac{1900}{\sqrt{1-\dfrac{0.92^2c^2}{c^2}}}\\\Rightarrow \rho=\dfrac{1900}{\sqrt{1-0.92^2}}\\\Rightarrow \rho=4847.94844926\ kg/m^3

The cube's density as measured by an experimenter in the laboratory is 4847.94844926 kg/m³

3 0
3 years ago
What is a transverse and longitudinal wave ?
kodGreya [7K]
Transverse waves travel perpendicular to neighboring wave motion like a slinky while longitudinal waves depend on the displacement of a medium which include sound waves.
8 0
3 years ago
Two 100 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Bat -10 m/s when th
tatiyna

Answer:

b) -10 m/s

Explanation:

In perfectly elastic head on collisions of identical masses, the velocities are exchanged with one another.

3 0
3 years ago
What units is time measured in
Artist 52 [7]

Answer:

The base unit for time is the second (the other SI units are: metre for length, kilogram for mass, ampere for electric current, kelvin for temperature, candela for luminous intensity, and mole for the amount of substance). The second can be abbreviated as s or sec.

Explanation:

6 0
3 years ago
A particle beam is made up of many protons, each with a kinetic energy of 3.25times 10-15 J. A proton has a mass of 1.673 times
ArbitrLikvidat [17]

Answer:

The magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 1.01 x 10^{-4} N/C

Explanation:

given information,

kinetic energy, KE = 3.25 x 10^{-15} J

proton's mass, m = 1.673 x 10^{-27} kg

charge, q = 1.602 x 10^{-19} C

distance, d = 2 m

to find the electric field that will stop the proton, we can use the following equation:

E = F/q

   = (KE/d) / q ,        KE = Fd --> F = KE/d

   = KE/qd

    = (3.25 x 10^{-15} J) / (1.602 x 10^{-19} C)(2 m)

    = 1.01 x 10^{-4} N/C

3 0
3 years ago
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