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3 years ago

the compound diborane can be used as a rocket propellant. what is the percent composition of boron in diborane

Chemistry

2 answers:

Blababa [14]3 years ago

3 0

Answer:

78.14 % B; 21.86 % H

Step-by-step explanation:

The formula of diborane is B₂H₆.

The masses of each element are:

2B = 2 × 10.81 = 21.62 u

6H = 6 × 1.008 = <u> 6.048 u </u>

TOTAL = 27.67 u

% B = 21.62/27.67 × 100

= 78.14 %

% H = 6.048/ 27.67

= 21.86 %

nikitadnepr [17]3 years ago

3 0

Answer:

22% for plato and edmentum users

Explanation:

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2 years ago

Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen

olga55 [171]

Answer: Rate law= $k[A]^1[B]^2$ , order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is $3L^2mol^{-2}s^{-1}$

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From trial 2: $4.8\times 10^{-2}=k[0.10]^x[0.40]^y$ (2)

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$4=2^y,2^2=2^y$ therefore y=2.

b) From trial 2: $4.8\times 10^{-2}=k[0.10]^x[0.40]^y$ (3)

From trial 3: $9.6\times 10^{-2}=k[0.20]^x[0.40]^y$ (4)

Dividing 4 by 3: $\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}$

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