The protons inside an atoms nucleus help bind the nucleus together. They also attract the negatively charged electons
Answer:
The substance has a specific heat of 1.176 J/g°C
Explanation:
<u>Step 1: </u>Data given
Temperature change = 34 °C
Mass of the substance = 20 kg = 20000 grams
The substance gained 800 kJ of heat during this temperature change
<u>Step 2:</u> Calculate the specific heat
q = m*c*ΔT
⇒ with q = heat gained = 800 kJ = 800000 J
⇒ with m = the mass of the substance = 20 kg = 20000 grams
⇒ with c = the specific heat of the substance = TO BE DETERMINED
⇒ with ΔT = the change of temperature = T2 -T1 = 48° - 14 ° = 34°
c = q/(m*ΔT)
c = 800000 / (20000 * 34)
c = 1.176 J/g°C
The substance has a specific heat of 1.176 J/g°C
Explanation:
First, let's convert 481 mmHg to atm:
1 atm --- 760 mmHg
x atm --- 481 mmHg
x = 0.63 atm
mmHg to Torr:
1 mmHg ---- 1 Torr
481 mmHg --- 481 Torr
481 Torr
mmHg to inHg
1 mmHg ---- 0.039 inHg
481 mmHg ---- y inHg
y = 18.8 inHg
mmHg to Pa
1 mmHg --- 133.322 Pa
481 mmHg ---- z
z = 64,128 Pa
Answer:
0.63 atm
481 Torr
18.8 inHg
64,128 Pa
Answer:
i have no clue
Explanation:
umm cause i have no clue sorry lol but good luck