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Thepotemich [5.8K]
1 year ago
11

Swift has a balloon of gas at 64psi. The volume of the balloon is 6.958L. If the volume of the balloon is reduced to 3L. what wi

ll the new pressure be in psi? (Assume the temperature is constant)
Chemistry
1 answer:
aniked [119]1 year ago
3 0

We could use the Boyle's law for gases.

This law states that:

P_1V_1=P_2V_2

Which means that at a constant temperature, as pressure increases, volume decreases. (P1 and V1 are the initial pressure and volume and P2 and V2 are the final pressure and volume respectively)

We could replace the values of the problem to get:

\begin{gathered} P_1=64psi \\ V_1=6.958L \\ P_2=? \\ V_2=3L \end{gathered}

Now, replacing in the equation:

\begin{gathered} 64psi\cdot6.958L=P_2\cdot3L \\ P_2=\frac{64psi\cdot6.958L}{3L}=148.44psi \end{gathered}

Therefore, the new pressure will be 148.44psi.

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Explanation:

First we convert 27 °C to K:

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With the absolute temperature we can use <em>Charles' law </em>to solve this problem. This law states that at constant pressure:

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Where in this case:

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We input the data:

300.16 K * 1600 m³ = T₂ * 1250 m³

And solve for T₂:

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