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Travka [436]
3 years ago
7

In what region of the electromagnetic spectrum is the frequency of the incident photon

Physics
1 answer:
Aliun [14]3 years ago
3 0
First and foremost, a photon is quantum of light. It is otherwise known as visible light and has a wavelength range of 400 to 700 nm. Moving waves are describable by their frequency (number of waves per second) and wavelengths.

A single photon can be considered unique from other photons only by its energy. In empty space (vacuum), all photons have the same speed or velocity. 

The frequency of the electromagnetic vibration, we know as light, is given in units of Hertz. One hertz is equivalent to one vibration per second; it must be noted that the range of spectrum perceived by the eye extends from 4.3 x 10∧ 14 Hz in the red to about 7.5 x 10∧ 14 Hz in the violet.
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What is necessary for a substance to be a conductor of electricity?
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3 0
3 years ago
When light is reflected by a mirror, the angle of incidence is always A. equal to the angle of reflection. B. less than the angl
ankoles [38]
When light is reflected by a mirror, the angle of incidence is always <span>A. equal to the angle of reflection. We know this by the Law of Reflection.</span>
6 0
3 years ago
Read 2 more answers
A boy whirls a stone in a horizontal circle of radius 1.4 m and at height 1.5 m above ground level. The string breaks, and the s
balandron [24]

Answer:233.23 m/s^2

Explanation:

Given

radius of circle=1.4 m

Height of stone above ground=1.5 m

Horizontal distance(R)=10 m

It is given at the time of break stone flies horizontally thus stone to cover a height of 1.5 m in time t before reaching ground

1.5=0+\frac{gt^2}{2}

t=0.55 s

Initial horizontal velocity at the time of break is given by u

R=u\times t

10=u\times 0.55

u=18.07 m/s

Therefore magnitude of centripetal acceleration is given by

a_c=\frac{u^2}{r}=\frac{18.07^2}{1.4}=233.23 m/s^2

6 0
3 years ago
A tennis ball is served horizontally from 2.4m above the ground at net is 12m away and point 0.9 high will be ball clear the net
Schach [20]

Explanation:

Let us first calculate  long does it take to go 12m at 30m/s( assumed speed)

12/30 = 0.4 seconds

horizontal distance the ball drop in that time

H= (0)(0.4)+1/2(-9.8)(0.4)2

H= -0.78m

negative sign shows that the height of the ball at the net from the top.

Height of the ball at the net and from the ground= H1-H=2.4-0.78=1.62m

As 1.62m>0.9m so the ball will clear the net.

H_1= V0y t’ + ½ g t’^2

-2.4= (0)t’ + ½ (-9.8) t’^2

t’= 0.69s

X’=V0x t’

X’=(30)(0.96)

X’= 20.7m

3 0
3 years ago
An object of mass 25kg is falling from the height h=10 m. calculate
r-ruslan [8.4K]

Answer:

a=2500J,b=1000K,c=1000J,d=14.142m/s

Explanation:

V²=U²+2gh

V²=0 + 2×10×10=200m/s

a).kinetic energy=(1/2)mv²=(1/2)25×200=2500

potential energy=mgh

p.e=25×10×10=2500J

pe+ke=2500+2500=5KJ

b).mgh=25×10×4=1000J

c). V²=U²+2gh

V²=0+2×10×4

V²=80

kinetic energy=(1/2)mv²

=(1/2)25×80

=1KJ

d). From my first paragraph V²=200

V=√200

V=14.142m/s

6 0
3 years ago
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