Answer:
the time taken for the object to fall is 6 s.
Explanation:
Given;
final velocity of the object, v = 58.8 m/s
initial velocity of the object, u = 0
The height of fall of the object is calculated as;
v² = u² + 2gh
v² = 2gh

The time to fall through the height is calculated as;

Therefore, the time taken for the object to fall is 6 s.
Answer:
T= 37 day
Explanation:
To solve this exercise we will use the definition of angular velocity as the angular distance, which for a full period is 2pi between time.
w = T / t
The relationship between angular and linear velocity is
v = w r
w = v / r
We substitute everything in the first equation
v / r = 2π / t
t = 2π r / v
Let's reduce to the SI system
V = 2 km / s (1000m / 1km) = 2 10³ m / s
r= R = 6.96 10⁸ m
Let's calculate
t = 2π 6.96 10⁸/2 10³
t = 3.2 10⁶ s
T = t = 3.2 10⁶ s ( 1h/3600s) (1 day/24 h)
T= 37 day
Her muscles were flaring with the blood coursing through her muscles.
Answer:
The answer is -x direction.
Explanation:
According to the right hand rule for electromagnetism, when the thumb points up, index finger points forward and the middle finger is perpendicular to the index finger, the thumb points in the direction of the magnetic force, the index finger in the direction of the charge movement and the middle finger in the direction of the electromagnetic lines. If the electric field is pointing in the -z direction which is into the screen and the magnetic field is in the +y direction which is upwards, then the magnetic lines are in the -x direction.
I hope this answer helps.
Explanation:
Given that,
Induced emf 
Rate of current = 0.250 A/s
Number of turns =30
(a). We need to calculate the mutual inductance of the pair of coils
Using formula of the mutual inductance




The mutual inductance of the pair of coils is 6.6 mHz.
(b). We need to calculate the flux through each turn
Using formula of flux

Put the value into the formula


The flux through each turn is 
(c). We need to calculate the magnitude of the induced emf in the first coil
Using formula of induced emf



The magnitude of the induced emf in the first coil is 
Hence, This is the required solution.