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asambeis [7]
3 years ago
5

Consider the diver and the board. Which object exerts the action force?

Physics
2 answers:
inna [77]3 years ago
7 0

Answer:

Explanation:

Which object exerts the action force?

diver

Which object exerts the reaction force?

diving board

In what direction does the action force push?

down

In what direction does the reaction force push?

up

Elina [12.6K]3 years ago
4 0

Could I please have more information?

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If an object falls and ends with a velocity of 58.8 m/s, how long was the<br><br> object falling?
tensa zangetsu [6.8K]

Answer:

the time taken for the object to fall is 6 s.

Explanation:

Given;

final velocity of the object, v = 58.8 m/s

initial velocity of the object, u = 0

The height of fall of the object is calculated as;

v² = u² + 2gh

v² = 2gh

h = \frac{v^2}{2g} \\\\h = \frac{(58.8)^2}{2(9.8)} \\\\h = 176.4 \ m

The time to fall through the height is calculated as;

h =ut+  \frac{1}{2} gt^2\\\\h = 0 +  \frac{1}{2} gt^2\\\\h =  \frac{1}{2} gt^2\\\\t= \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 176.4}{9.8} } \\\\t = 6 \ s

Therefore, the time taken for the object to fall is 6 s.

6 0
3 years ago
From Doppler shifts of the spectral lines in the light coming from the east and west edges of the Sun, astronomers find that the
Gala2k [10]

Answer:

T= 37 day

Explanation:

To solve this exercise we will use the definition of angular velocity as the angular distance, which for a full period is 2pi between time.

    w = T / t

The relationship between angular and linear velocity is

    v = w r

    w = v / r

We substitute everything in the first equation

    v / r = 2π / t

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Let's reduce to the SI system

    V = 2 km / s (1000m / 1km) = 2 10³ m / s

    r= R = 6.96 10⁸ m

Let's calculate

    t = 2π 6.96 10⁸/2 10³

    t = 3.2 10⁶ s

    T = t = 3.2 10⁶ s ( 1h/3600s) (1 day/24 h)

    T= 37 day

3 0
3 years ago
What is a sentence for absolute strength?
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Her muscles were flaring with the blood coursing through her muscles.
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An excited hydrogen atom releases an electromagnetic wave to return to its normal state. You use your futuristic dual electric/m
ryzh [129]

Answer:

The answer is -x direction.

Explanation:

According to the right hand rule for electromagnetism, when the thumb points up, index finger points forward and the middle finger is perpendicular to the index finger, the thumb points in the direction of the magnetic force, the index finger in the direction of the charge movement and the middle finger in the direction of the electromagnetic lines. If the electric field is pointing in the -z direction which is into the screen and the magnetic field is in the +y direction which is upwards, then the magnetic lines are in the -x direction.

I hope this answer helps.

6 0
3 years ago
Two coils are wound around the same cylindrical form. When the current in the first coil is decreasing at a rate of -0.250 A/s,
sdas [7]

Explanation:

Given that,

Induced emf \epsilon= 1.65\times10^{-3}\ V

Rate of current = 0.250 A/s

Number of turns =30

(a). We need to calculate the mutual inductance of the pair of coils

Using formula of the mutual inductance

M=\dfrac{\epsilon}{|\dfrac{\Delta i}{\Delta t}|}

M=\dfrac{1.65\times10^{-3}}{0.250}

M=0.0066=6.6\times10^{-3}\ Hz

M=6.6\ mHz

The mutual inductance of the pair of coils is 6.6 mHz.

(b). We need to calculate the flux through each turn

Using formula of flux

\phi_{B}=\dfrac{Mi}{N}

Put the value into the formula

\phi_{B}=\dfrac{6.6\times10^{-3}\times1.25}{30}

\phi_{B}=0.000275 =2.75\times10^{-4}\ Wb

The flux through each turn is 2.75\times10^{-4}\ Wb

(c). We need to calculate the magnitude of the induced emf in the first coil

Using formula of induced emf

\epsilon=M|\dfrac{\Delta i_{2}}{\Delta t}|

\epsilon=6.6\times10^{-3}\times0.3

\epsilon=0.00198 =1.98\times10^{-3}\ mV

The magnitude of the induced emf in the first coil is 1.98\times10^{-3}\ mV

Hence, This is the required solution.

8 0
3 years ago
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