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asambeis [7]
3 years ago
5

Consider the diver and the board. Which object exerts the action force?

Physics
2 answers:
inna [77]3 years ago
7 0

Answer:

Explanation:

Which object exerts the action force?

diver

Which object exerts the reaction force?

diving board

In what direction does the action force push?

down

In what direction does the reaction force push?

up

Elina [12.6K]3 years ago
4 0

Could I please have more information?

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A motorcyclist travels with an average speed of 6 m/s . If the cyclist is going to a friend's house 36 m away , how much time wi
vodka [1.7K]

Answer:

<h2>6 s</h2>

Explanation:

The time taken by the cyclist can be found by using the formula

t  = \frac{d}{v}  \\

v is the velocity

d is the distance

From the question we have

t =  \frac{36}{6}  \\  = 6

We have the final answer as

<h3>6 s</h3>

Hope this helps you

5 0
3 years ago
A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an accelerat
Gekata [30.6K]

Answer:

The force required to move the quarterback with linebacker is <u>1215 N</u>

Explanation:

\text { Mass of linebacker } \mathrm{m}_{2}=150 \mathrm{kg}

\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}

\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}

Using Newton's second law, it is established that  F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object \left(m_{1}+m_{2}\right)

Now consider both \mathrm{m}_{1} \text { and } \mathrm{m}_{2}as a system, so net force acting on the system is \text { Force }=\left(m_{1}+m_{2}\right) a

Substitute the given values in the above formula,

\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

Force = 1215 N

<u>1215 N </u>is the force required to move the quarterback with linebacker.

5 0
4 years ago
You push a 50 kg wooden box across a wooden floor at a constant speed of 1.0 m/s. The coefficient of kinetic friction is 0.15. N
WARRIOR [948]

Answer:

0.68 seconds

Explanation:

Data provided in the question:

Mass of the box = 50 kg

Speed of the box = 1.0 m/s

Coefficient of friction, μ = 0.15

Now,

Force applied = μmg    

Here,

g is the acceleration due to gravity = 9.8 m/s²

Thus,

F = 0.15 × 50 × 9.8

= 73.5 N

Also,

Force = Mass × Acceleration

thus,

73.5 N = 50 × a

or

a = 1.47 m/s²

After doubling the speed

Final speed = 2 × Initial speed

= 2 × 1 m/s

= 2 m/s

Also,

Acceleration = [change in speed] ÷ Time

or

1.47 = [ 2 - 1 ] ÷ Time

or

Time = 1 ÷ 1.47

or

Time = 0.68 seconds

6 0
4 years ago
If a force does a positive amount of work on an object, does the object’s speed increase, decrease, or remain the same? Justify
iris [78.8K]

Answer:

see that there is no dependence on speed, so the work remains constant

Explanation:

Work is defined by the expression

        W = F. d

where the boldface indicates vectors, this equation can be written in scalar form

         W = f d cos θ

where θ is the angle between force and displacement.

We see that there is no dependence on speed, so the work remains constant

The power is

           P = W / t

           P = f d / t

           p = F v

we see that the power is the one that depends on the speed of the body

6 0
3 years ago
Hey can someone please help me and can u show your work plz plz plz plz
Tju [1.3M]

Answer:

Good luck

Explanation:

4 0
3 years ago
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