I think true. I'm pretty sure, but check w/ others too.
The answer is true
Step by step explanation:
Answer:
The work done by the steam is 213 kJ.
Explanation:
Given that,
Mass = 5 kg
Pressure = 150 kPa
Temperature = 200°C
We need to calculate the specific volume
Using formula of work done



Where,R = gas constant
T = temperature
P = pressure
=Atmosphere pressure
m = mass
Put the value into the formula


Hence, The work done by the steam is 213 kJ.
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