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3 years ago

How is a mineral of volcanic origin with large crystals most likely formed?

Physics

2 answers:

Slav-nsk [51]3 years ago

5 0

Answer:

(Correct option is 2) crystallization of molten material inside Earth.

Explanation:

There are three types of rocks found on the surface of the earth sedimentary, metamorphic, and igneous. Rocks which have hardened with the help of magma, and the hot liquid below the earth crust is known as igneous rocks.

Igneous rock is defined as a rock which is synthesized by the crystallization, and hardening of molten material which originates from the inside of the Earth. It is basically two types:

1) Extrusive rocks.

2) Intrusive rocks.

lilavasa [31]3 years ago

3 0

Answer:

Explanation:

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Professional Application: A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 11

Nataliya [291]

Answer:

0.182 m/s

Explanation:

m1 = 30,000 kg, m2 = 110,000 kg, u1 = 0.85 m/s

let the velocity of loaded freight car is v

Use the conservation of momentum

m1 x u1 + m2 x 0 = (m1 + m2) x v

30,000 x 0.85 = (30,000 + 110,000) x v

v = 0.182 m/s

5 0

2 years ago

Which is better? ( Gifting or Receiving )

Katen [24]

Honestly, giving. I know that receiving may feel very good, and you get that new thing that you wanted but if you give, you feel really good when you see that smile on someone else’s face.

3 0

2 years ago

A solid conducting sphere of radius 2.00 cm has a charge of 6.88 μC. A conducting spherical shell of inner radius 4.00 cm and ou

zepelin [54]

Explanation:

Given that,

Radius R= 2.00

Charge = 6.88 μC

Inner radius = 4.00 cm

Outer radius = 5.00 cm

Charge = -2.96 μC

We need to calculate the electric field

Using formula of electric field

$E=\dfrac{kq}{r^2}$

(a). For, r = 1.00 cm

Here, r<R

So, E = 0

The electric field does not exist inside the sphere.

(b). For, r = 3.00 cm

Here, r >R

The electric field is

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times6.88\times10^{-6}}{(3.00\times10^{-2})^2}$

$E=6.88\times10^{7}\ N/C$

The electric field outside the solid conducting sphere and the direction is towards sphere.

(c). For, r = 4.50 cm

Here, r lies between R₁ and R₂.

So, E = 0

The electric field does not exist inside the conducting material

(d). For, r = 7.00 cm

The electric field is

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times(-2.96\times10^{-6})}{(7.00\times10^{-2})^2}$

$E=5.43\times10^{6}\ N/C$

The electric field outside the solid conducting sphere and direction is away of solid sphere.

Hence, This is the required solution.

6 0

2 years ago

What kind of education is required to be a ocean engineer?

ra1l [238]

To become an ocean engineer, the job would require a B<span>achelors degree in ocean engineering.

Hope this helps.</span>

4 0

3 years ago

A driver starts his parked car and within 4.6 seconds, reaches a velocity of 15 m/s. What is his acceleration?

myrzilka [38]

Answer: 6.
All of the numbers in every row and column add up to 15! (Also, 6 is the only number not represented out of numbers 1 through 9.)
And to the representation to his problem you can clear,y see that 4.6 seconds is actully the the time of the whole parking. so if you just do a simple equation... 4.6x10p/2x15/10x2 would get your answer to 6

5 0

2 years ago