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3 years ago

How much heat is needed to raise the temperature of 8grams of water by 19°C

Physics

1 answer:

777dan777 [17]3 years ago

4 0

Answer:

635.36J

Explanation:

The formulae to apply in this question is;

q=m*c*ΔФ where q is the heat needed, m is mass,c is specific heat capacity and ΔФ is change in temperatures

Given that;

m=8 g

ΔФ= 19°C - 0°C= 19°C

c=4.18J/g.°C

Substitute values

q= 8×4.18×19 = 635.36J

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<h3>How to find the magnitude of the force that the beam exerts on the hi.nge?</h3>

Let's draw the free body diagram of the system using the given data.
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For that, it is given that the horizontal component of force is equal to the 86.62N, which is same as that of the horizontal component of normal reaction that exerts by the beam on the hi.nge.

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$N_y=F_V=mg-Tsin59\\$

To find Ny, we need to find the tension T.
For this, we can equate the net horizontal force.

$F_H=N_x=Tcos59\\\\T=\frac{F_H}{cos59} =\frac{86.62}{0.51}= 169.84N$

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$N=\sqrt{N_x^2+N_y^2} =\sqrt{(86.62)^2+(246.4)^2}=261.12N$

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