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Irina-Kira [14]
3 years ago
5

A tennis ball is served horizontally from 2.4m above the ground at net is 12m away and point 0.9 high will be ball clear the net

where will be ball land
Physics
1 answer:
Schach [20]3 years ago
3 0

Explanation:

Let us first calculate  long does it take to go 12m at 30m/s( assumed speed)

12/30 = 0.4 seconds

horizontal distance the ball drop in that time

H= (0)(0.4)+1/2(-9.8)(0.4)2

H= -0.78m

negative sign shows that the height of the ball at the net from the top.

Height of the ball at the net and from the ground= H1-H=2.4-0.78=1.62m

As 1.62m>0.9m so the ball will clear the net.

H_1= V0y t’ + ½ g t’^2

-2.4= (0)t’ + ½ (-9.8) t’^2

t’= 0.69s

X’=V0x t’

X’=(30)(0.96)

X’= 20.7m

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Answer:

See explanation

Explanation:

In this exercise, we need to use the law of conservation of angular momentum which is:

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W: angular velocity

Now let's call 1 the runner and 2, the turntable. the system would be W2'.

The angular speed of the runner, we can calculate that with the following expression:

W = V/r

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The innertia is calculated with the expression:

I = m*r²

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