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3 years ago

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A spherical mirror is polished on both sides. When the concave side is used as a mirror, the magnification is 4.4. What is the m

agnification when the convex side is used as a mirror, the object remaining the same distance from the mirror?

1 answer:

patriot [66]3 years ago

8 0

Answer:

$m = \frac{-4.4}{7.4}$

Explanation:

magnification is the ratio of distance of image to distance of object

i.e. $m = -\frac{d_i}{d_o}$

$d_i = -4.4 d_o$

As per the lens equation,

$\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f}$

We will calculate the focal length of the mirror

$\frac{1}{yd_o} + \frac{1}{-4.4d_o} = \frac{1}{f} \\\frac{4.4 -1}{4.4} \frac{1}{d_o} = \frac{1}{f}\\f = \frac{4.4}{3.4} d_o$

Now for convex mirror only the sign will change

Thus, focal length would be equal to

$f = - \frac{4.4}{3.4} d_o$

Plugging this value into lens equation, we get

$\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f} \\\frac{1}{d_o} + \frac{1}{d_i} = \frac{-3.4}{4.4} \frac{1}{d_o} \\\frac{7.4}{4.4} \frac{1}{d_o} = \frac{1}{d_i}\\\frac{d_i}{d_o} = \frac{4.4}{7.4} \\m =- \frac{d_i}{d_o} \\\\m = - \frac{4.4}{7.4}$

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1 year ago

A magnetic field of 37.2 t has been achieved at the mit francis bitter national magnetic laboratory. Find the current needed to

jeka57 [31]

Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire $=3.7\ MA$

b) Current at the center of the circular coil $=2.48\times 10^{5}\ A$

c) Current near the center of a solenoid $236.8\ A$

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where $B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}$

$\mu=4\pi \times 10^{-7}\ \frac{henry}{m}$

Plugging the values,

Conversion $1\times 10^6 A = 1\ MA$ ,and $2cm=\frac{2}{100}=0.02\ m$

$I=\frac{37.2\times \ 2\pi(0.02)}{4\ \pi \times (10^{-7})}=3.7\ MA$

⇒Magnetic Field at the center due to circular coil (at center) is given by, $B=\frac{\mu\times I (N)}{2(a)}$

So $I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A$

⇒Magnetic field due to the long solenoid, $B=\mu\ nI=\mu (\frac{N}{l})I$

Then $I=\frac{B}{\mu(\frac{N}{L})} \approx 236.8\A$

So the value of current are $3.7 MA$ , $2.48\times 10^{5} A$ and $236.8\ A$ respectively.

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3 years ago

a bus is moving at 22m/s [E] for 12s. Then the bus driver slows down at 1.2m/s2 [W] until the bus stops. Determine the total dis

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The total displacement is equal to the total distance. For the east or E direction, the distance is determined using the equation:

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For the west or W direction, we use the equations:
a = (v - v₀)/t
d = v₀t + 0.5at²

Because the object slows down, the acceleration is negative. So,
-1.2 m/s² = (0 m/s - 22 m/s)/t
t = 18.33 seconds
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3 years ago

Two long, parallel wires are separated by 2.2 mm. Each wire has a 32-AA current, but the currents are in opposite directions. Pa

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Answer:

$B=1.1636*10^{-3}T$

Explanation:

Given data

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To find

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Solution

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