1. Calcular la masa de mercurio que pasó de 30 °C hasta 120 °C y absorbió 4400 cal. Calor específico del
1 answer:
Answer:
Masa, m = 0.088 kg
Explanation:
Given the following data;
Temperatura inicial = 30°C
Temperatura final = 120°C
Capacidad calorífica específica = 138J/kg.K
Calor absorbido, Q = 4400 cal.
Para encontrar la masa;
La capacidad calorífica viene dada por la fórmula;
Dónde;
Q representa la capacidad calorífica o la cantidad de calor.
m representa la masa de un objeto.
c representa la capacidad calorífica específica del agua.
dt representa el cambio de temperatura.
dt = T2 - T1
dt = 120 - 30
dt = 90°C to kelvin = 273 + 90 = 363K
Sustituyendo en la fórmula, tenemos;
Masa, m = 0.088 kg
You might be interested in
The atom must lose 2 electrons
Explanation:
An atom consists of three types of particles:
- Protons, in the nucleus, with positive electric charge
- Neutrons, in the nucleus, with no electric charge
- Electrons, orbiting around the nucleus, with negative electric charge
As a result, the net electric charge of an atom is given by the number of protons minus the number of electrons:
Q = #p - #e
For a neutral atom, the number of protons and electrons is the same, so the net charge is zero.
In order for an atom to have a positive charge of +2, it means that there must be 2 protons more than the number of electrons. Since atoms exchange electrons (and not protons), this means that the atom must have "lost" 2 electrons.
In this problem, we have an atom with 13 protons: this means that initially it also has 13 electrons. However, later the atom lost 2 electrons, and as a result, the final charge is +2e.
Learn more about atoms:
#LearnwithBrainly