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timofeeve [1]
3 years ago
10

Consider the formation of hcn by the reaction of nacn (sodium cyanide) with an acid such as h2so4 (sulfuric acid): 2nacn(s)+h2so

4(aq)âna2so4(aq)+2hcn(g) what mass of nacn gives the lethal dose in the room?
Chemistry
2 answers:
dem82 [27]3 years ago
7 0

Answer:

18.0 g

Explanation:

There is some info missing. I think this is the original question.

<em>Hydrogen cyanide, HCN, is a poisonous gas. The lethal dose is approximately 300 mg HCN per kilogram of air when inhaled. The density of air at 26 °C is 1.18 kg/m³. </em>

<em> Consider the formation of HCN by the reaction of NaCN (sodium cyanide) with an acid such as H₂SO₄ (sulfuric acid): </em>

<em>2 NaCN(s) + H₂SO₄(aq) → Na₂SO₄(aq) + 2 HCN(g) </em>

<em>What mass of NaCN gives the lethal dose in the 28.0 m³ room? Express your answer to three significant figures and include the appropriate units.</em>

<em />

The density of air is 1.18 kg/m³. The mass represented by 28 m³ is:

28.0 m³ × (1.18 kg/m³) = 33.0 kg

The lethal dose is approximately 300 mg HCN per kilogram of air. The lethal dose of HCN in 33.0 kg of air is:

33.0 kg air × (300 mg HCN / 1 kg air) = 9900 mg HCN = 9.90 g HCN

From the balanced equation, we can establish the following relations:

  • The molar mass of HCN is 27.03 g/mol.
  • The molar ratio of HCN to NaCN is 2:2.
  • The molar mass of NaCN is 49.01 g/mol.

The mass of NaCN that produces 9.90 g of HCN is:

9.90gHCN.\frac{1molHCN}{27.03gHCN} .\frac{2molNaCN}{2molHCN} .\frac{49.01gNaCN}{1molNaCN} =18.0gNaCN

Artemon [7]3 years ago
5 0

2NaCN(s) + H₂SO₄(aq) --> Na₂SO₄(aq) + 2HCN(g)  

The molar ratio between NaCN : HCN is 2:2  or 1:1

Mass of HCN = 16.7 g

Molar mass of HCN = 1 + 12 + 14 = 27 g/mol

Molar mass of NaCN = 49 g/mol

Therefore, the mass of NaCN is

16.7 g of  HCN x 49 g/mol of NaCN / 27 g/mol of HCN = 30.3 grams of NaCN

Therefore, 30.3 grams of NaCN gives the lethal dose in the room.

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Unknown element x has four energy levels, five valence electrons, and is a metalloid. what is elements x?
kykrilka [37]

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Element X is Arsenic (As)

Explanation:

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Five different substances are given to you to be dissolved in water. Which substances are most likely to undergo dissolution in
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27. The density of nickel is 8.91 g/cm3. How large a cube, in cm3, would contain 2.00 x 10^24 atoms of nickel? Use dimensional a
jok3333 [9.3K]

Answer : The volume of the cube is, 21.88cm^3

Solution : Given,

Density of nickel = 8.91g/cm^3

Number of nickel atoms = 2\times 10^{24}

Molar mass of nickel = 58.7 g/mole

First we have to calculate the moles of nickel.

As, 6.022\times 10^{23} atoms form 1 mole of nickel

So, 2\times 10^{24} atoms form \frac{2\times 10^{24}}{6.022\times 10^{23}}=3.321 moles of nickel

The moles of nickel = 3.321 moles

Now we have to calculate the mass of nickel.

\text{ Mass of Ni}=\text{ Moles of Ni}\times \text{ Molar mass of Ni}

\text{ Mass of Ni}=(3.321moles)\times (58.7g/mole)=194.94g

The mass of nickel = 194.94 g

Now we have to calculate the volume of nickel.

Density=\frac{Mass}{Volume}

8.91g/cm^3=\frac{194.94g}{Volume}

Volume=21.88cm^3

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